How to resolve the algorithm Leap year step by step in the Oz programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Leap year step by step in the Oz programming language
Table of Contents
Problem Statement
Determine whether a given year is a leap year in the Gregorian calendar.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Leap year step by step in the Oz programming language
Source code in the oz programming language
declare
fun {IsLeapYear Year}
case Year mod 100 of 0 then
Year mod 400 == 0
else
Year mod 4 == 0
end
end
in
for Y in [1900 1996 1997 2000] do
if {IsLeapYear Y} then
{System.showInfo Y#" is a leap year."}
else
{System.showInfo Y#" is NOT a leap year."}
end
end
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