Step by Step solution about How to resolve the algorithm Leonardo numbers step by step in the Ruby programming language

The code snippet is a Ruby implementation of the Leonardo sequence, a sequence of numbers defined recursively by the following rules:

• The first two terms are both 1.
• Each subsequent term is the sum of the previous two terms, plus an optional increment value.

The code defines a function called leonardo that takes three optional parameters:

• l0: The first term of the sequence.
• l1: The second term of the sequence.
• add: The increment value.

The function returns an enumerator if no block is given, or it yields each term of the sequence to the block if a block is given.

The code then prints the first 25 terms of the Leonardo sequence, using the default values for the first two terms and increment value (l0=1, l1=1, add=1). It then prints the first 25 terms of the sequence with the first two terms set to 0 and 1, and the increment value set to 0 (l0=0, l1=1, add=0).

Here is an example of the output:

[1, 1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843, 1364, 2207, 3571, 5778, 9349, 15127, 24476, 39603, 64079, 103682]
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025]

def leonardo(l0=1, l1=1, add=1)
  return to_enum(__method__,l0,l1,add) unless block_given?
  loop do  
    yield l0
    l0, l1 = l1, l0+l1+add
  end
end

p leonardo.take(25)
p leonardo(0,1,0).take(25)