How to resolve the algorithm Levenshtein distance step by step in the Crystal programming language
How to resolve the algorithm Levenshtein distance step by step in the Crystal programming language
Table of Contents
Problem Statement
In information theory and computer science, the Levenshtein distance is a metric for measuring the amount of difference between two sequences (i.e. an edit distance). The Levenshtein distance between two strings is defined as the minimum number of edits needed to transform one string into the other, with the allowable edit operations being insertion, deletion, or substitution of a single character.
The Levenshtein distance between "kitten" and "sitting" is 3, since the following three edits change one into the other, and there isn't a way to do it with fewer than three edits:
The Levenshtein distance between "rosettacode", "raisethysword" is 8. The distance between two strings is same as that when both strings are reversed.
Implements a Levenshtein distance function, or uses a library function, to show the Levenshtein distance between "kitten" and "sitting".
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Levenshtein distance step by step in the Crystal programming language
Source code in the crystal programming language
require "levenshtein"
puts Levenshtein.distance("kitten", "sitting")
puts Levenshtein.distance("rosettacode", "raisethysword")
module Levenshtein
def self.distance(a, b)
a, b = a.downcase, b.downcase
costs = (0..b.size).to_a
(1..a.size).each do |i|
costs[0], nw = i, i - 1 # j == 0; nw is lev(i-1, j)
(1..b.size).each do |j|
costs[j], nw = [costs[j] + 1, costs[j-1] + 1, a[i-1] == b[j-1] ? nw : nw + 1].min, costs[j]
end
end
costs[b.size]
end
def self.test
%w{kitten sitting saturday sunday rosettacode raisethysword}.each_slice(2) do |(a, b)| #or do |pair| a, b = pair
puts "distance(#{a}, #{b}) = #{distance(a, b)}"
end
end
end
Levenshtein.test
def levenshtein_distance(str1, str2)
n, m = str1.size, str2.size
max = n / 2
return 0 if n == 0 || m == 0
return n if (n - m).abs > max
d = (0..m).to_a
x = 0
str1.each_char_with_index do |char1, i|
e = i + 1
str2.each_char_with_index do |char2, j|
cost = (char1 == char2) ? 0 : 1
x = [ d[j+1] + 1, # insertion
e + 1, # deletion
d[j] + cost # substitution
].min
d[j] = e
e = x
end
d[m] = x
end
x
end
%w{kitten sitting saturday sunday rosettacode raisethysword}.each_slice(2) do |(a, b)| #or do |pair| a, b = pair
puts "distance(#{a}, #{b}) = #{levenshtein_distance(a, b)}"
end
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