How to resolve the algorithm Linear congruential generator step by step in the Scala programming language
How to resolve the algorithm Linear congruential generator step by step in the Scala programming language
Table of Contents
Problem Statement
The linear congruential generator is a very simple example of a random number generator. All linear congruential generators use this formula:
Where:
If one chooses the values of
a
{\displaystyle a}
,
c
{\displaystyle c}
and
m
{\displaystyle m}
with care, then the generator produces a uniform distribution of integers from
0
{\displaystyle 0}
to
m − 1
{\displaystyle m-1}
. LCG numbers have poor quality.
r
n
{\displaystyle r_{n}}
and
r
n + 1
{\displaystyle r_{n+1}}
are not independent, as true random numbers would be. Anyone who knows
r
n
{\displaystyle r_{n}}
can predict
r
n + 1
{\displaystyle r_{n+1}}
, therefore LCG is not cryptographically secure. The LCG is still good enough for simple tasks like Miller-Rabin primality test, or FreeCell deals. Among the benefits of the LCG, one can easily reproduce a sequence of numbers, from the same
r
0
{\displaystyle r_{0}}
. One can also reproduce such sequence with a different programming language, because the formula is so simple. The task is to replicate two historic random number generators. One is the rand() function from BSD libc, and the other is the rand() function from the Microsoft C Runtime (MSCVRT.DLL). Each replica must yield the same sequence of integers as the original generator, when starting from the same seed. In these formulas, the seed becomes
s t a t
e
0
{\displaystyle state_{0}}
. The random sequence is
r a n
d
1
{\displaystyle rand_{1}}
,
r a n
d
2
{\displaystyle rand_{2}}
and so on.
The BSD formula was so awful that FreeBSD switched to a different formula. More info is at Random number generator (included)#C.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Linear congruential generator step by step in the Scala programming language
Source code in the scala programming language
object LinearCongruentialGenerator {
def bsdRandom(rseed:Int):Iterator[Int]=new Iterator[Int]{
var seed=rseed
override def hasNext:Boolean=true
override def next:Int={seed=(seed * 1103515245 + 12345) & Int.MaxValue; seed}
}
def msRandom(rseed:Int):Iterator[Int]=new Iterator[Int]{
var seed=rseed
override def hasNext:Boolean=true
override def next:Int={seed=(seed * 214013 + 2531011) & Int.MaxValue; seed >> 16}
}
def toString(it:Iterator[Int], n:Int=20)=it take n mkString ", "
def main(args:Array[String]){
println("-- seed 0 --")
println("BSD: "+ toString(bsdRandom(0)))
println("MS : "+ toString(msRandom(0)))
println("-- seed 1 --")
println("BSD: "+ toString(bsdRandom(1)))
println("MS : "+ toString( msRandom(1)))
}
}
You may also check:How to resolve the algorithm Inheritance/Single step by step in the Fortran programming language
You may also check:How to resolve the algorithm Set, the card game step by step in the Quackery programming language
You may also check:How to resolve the algorithm Fivenum step by step in the SAS programming language
You may also check:How to resolve the algorithm Forest fire step by step in the PHP programming language
You may also check:How to resolve the algorithm Sphenic numbers step by step in the C programming language