Step by Step solution about How to resolve the algorithm Literals/Integer step by step in the C++ programming language

This C++ code is a simple program that uses the conditional operator (ternary operator) to compare two expressions and print the result.

A step-by-step explanation of the code:

1. #include <iostream>: This line includes the input-output stream library, which is necessary for using std::cout.

2. int main(): This is the main function of the program where execution begins. It returns an integer (0 in this case).

3. std::cout << ( (727 == 0x2d7) && (727 == 01327) ? "true" : "false") << std::endl;:

   • (727 == 0x2d7): This expression checks if the decimal integer 727 is equal to the hexadecimal integer 0x2d7 (which is also 727). This condition is true.
   • (727 == 01327): This expression checks if the decimal integer 727 is equal to the octal integer 01327 (which is also 727). This condition is also true.
   • (727 == 0x2d7) && (727 == 01327): This combines the two conditions using the logical AND operator (&&). Since both conditions are true, the result of the expression is true.
   • ? "true" : "false": This is the conditional operator. Since the expression before the question mark is true, it evaluates to "true".
   • std::cout << ... << std::endl;: This line prints the result ("true" in this case) to the standard output (usually the console).

4. return 0;: This line indicates the end of the main function and the end of the program. It returns 0 to the operating system, indicating that the program executed successfully.

When you run this program, it will print "true" to the console because both conditions in the conditional operator are true.

#include <iostream>

int main()
{
  std::cout << ( (727 == 0x2d7) && 
                 (727 == 01327)     ? "true" : "false")
            << std::endl;
 
  return 0;
}