Step by Step solution about How to resolve the algorithm Long year step by step in the Go programming language

The provided Go code snippet is designed to identify and print the "long years" within specified centuries. Long years are years that have 53 weeks instead of the typical 52. This is determined based on the ISO 8601 week numbering system.

• import statements: The code starts by importing the necessary packages:

  • fmt for input and output operations
  • time for working with dates and times

• main function: The program's entry point is the main function.

• centuries and starts arrays:

  • centuries is an array of strings representing the centuries under consideration, in this case, the "20th", "21st", and "22nd" centuries.
  • starts is an array of integers representing the starting years of the respective centuries, in this case, 1900, 2000, and 2100.

• for loop over centuries: The program iterates over the centuries array using a for loop. For each century:

• longYears array initialization: It initializes an empty longYears array to store the long years within that century.

• fmt.Printf: The program prints a message indicating the current century being processed.

• Nested for loop over years:

  • A nested for loop iterates through the years within the current century.
  • The loop variable j represents the year under consideration.

• time.Date: For each year j, it creates a time.Time value t representing December 28th of that year. This date is used because it falls within the 53rd week if the year is a long year.

• ISOWeek method: The ISOWeek method is called on t to determine the ISO week number for that date.

• if statement: If the ISO week number is 53, it indicates a long year. In that case, the year j is appended to the longYears array.

• fmt.Println: After processing all years within the century, the program prints the longYears array, which contains the long years for that century.

package main

import (
    "fmt"
    "time"
)

func main() {
    centuries := []string{"20th", "21st", "22nd"}
    starts := []int{1900, 2000, 2100} 
    for i := 0; i < len(centuries); i++ {
        var longYears []int
        fmt.Printf("\nLong years in the %s century:\n", centuries[i])
        for j := starts[i]; j < starts[i] + 100; j++ {
            t := time.Date(j, time.December, 28, 0, 0, 0, 0, time.UTC)
            if _, week := t.ISOWeek(); week == 53 {
                longYears = append(longYears, j)
            }
        }
        fmt.Println(longYears)
    }
}