How to resolve the algorithm Loop over multiple arrays simultaneously step by step in the OCaml programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Loop over multiple arrays simultaneously step by step in the OCaml programming language

Table of Contents

Problem Statement

Loop over multiple arrays   (or lists or tuples or whatever they're called in your language)   and display the   i th   element of each. Use your language's   "for each"   loop if it has one, otherwise iterate through the collection in order with some other loop.

For this example, loop over the arrays: to produce the output:

If possible, also describe what happens when the arrays are of different lengths.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Loop over multiple arrays simultaneously step by step in the OCaml programming language

Source code in the ocaml programming language

let a1 = [| 'a'; 'b'; 'c' |]
and a2 = [| 'A'; 'B'; 'C' |]
and a3 = [| '1'; '2'; '3' |] ;;

Array.iteri (fun i c1 ->
  print_char c1;
  print_char a2.(i);
  print_char a3.(i);
  print_newline()
) a1 ;;

let n_arrays_iter ~f = function
  | [] -> ()
  | x::xs as al ->
      let len = Array.length x in
      let b = List.for_all (fun a -> Array.length a = len) xs in
      if not b then invalid_arg "n_arrays_iter: arrays of different 
length";
      for i = 0 to pred len do
        let ai = List.map (fun a -> a.(i)) al in
        f ai
      done

val n_arrays_iter : f:('a list -> unit) -> 'a 
array list -> unit

let () =
  n_arrays_iter [a1; a2; a3] ~f:(fun l ->
    List.iter print_char l;
    print_newline());
;;

  

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