How to resolve the algorithm Loops/Break step by step in the Aime programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Loops/Break step by step in the Aime programming language
Table of Contents
Problem Statement
Show a loop which prints random numbers (each number newly generated each loop) from 0 to 19 (inclusive).
If a number is 10, stop the loop after printing it, and do not generate any further numbers.
Otherwise, generate and print a second random number before restarting the loop.
If the number 10 is never generated as the first number in a loop, loop forever.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Loops/Break step by step in the Aime programming language
Source code in the aime programming language
integer
main(void)
{
integer a, b;
while (1) {
a = drand(19);
o_integer(a);
o_byte('\n');
if (a == 10) {
break;
}
b = drand(19);
o_integer(b);
o_byte('\n');
}
return 0;
}
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