How to resolve the algorithm Loops/Break step by step in the AutoHotkey programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Loops/Break step by step in the AutoHotkey programming language
Table of Contents
Problem Statement
Show a loop which prints random numbers (each number newly generated each loop) from 0 to 19 (inclusive).
If a number is 10, stop the loop after printing it, and do not generate any further numbers.
Otherwise, generate and print a second random number before restarting the loop.
If the number 10 is never generated as the first number in a loop, loop forever.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Loops/Break step by step in the AutoHotkey programming language
Source code in the autohotkey programming language
Loop
{
Random, var, 0, 19
output = %output%`n%var%
If (var = 10)
Break
Random, var, 0, 19
output = %output%`n%var%
}
MsgBox % output
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