How to resolve the algorithm Loops/Continue step by step in the Haskell programming language

Published on 7 June 2024 03:52 AM

How to resolve the algorithm Loops/Continue step by step in the Haskell programming language

Table of Contents

Problem Statement

Show the following output using one loop.

Try to achieve the result by forcing the next iteration within the loop upon a specific condition, if your language allows it.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Loops/Continue step by step in the Haskell programming language

The given Haskell code is a simple program that takes input from 1 to 10 and prints each number x according to the below rules:

  • If x is divisible by 5, print the number.
  • Otherwise, print the number followed by a comma and a space , .

Detailed Explanation:

  1. import Control.Monad (forM): This line imports the forM function from the Control.Monad module. The forM function applies a given function to each element of a list.

  2. main = forM [1..10] out: The main function is the entry point of the program. It applies the out function to each number in the list [1..10]. The [1..10] list comprehension generates a list of numbers from 1 to 10.

  3. out x | x mod 5 == 0 = print x: This line defines the out function. It takes an integer x as an argument and has two main cases:

    • If x is divisible by 5 (x mod 5 == 0), it prints x using the print function.
    • Otherwise, it continues to the next case.
  4. | otherwise = (putStr . (++", ") . show) x: In this case, it calls the putStr function, which prints a string to the standard output. The string is constructed using the (++", ") . show) expression. Let's break it down:

    • show x: Converts the integer x into a string representation.
    • (++", "): Appends a comma and a space , to the result of show x.
    • putStr: Prints the resulting string to the standard output.

So, for each number in the list, the program checks if it's divisible by 5, and if so, prints the number. If not, it prints the number followed by a comma and a space. The output is a list of numbers, separated by commas, with multiples of 5 printed on separate lines.

Example Output:

1, 2, 3, 4, 5
6, 7, 8, 9, 10

Source code in the haskell programming language

import Control.Monad (forM)
main = forM [1..10] out
    where
      out x | x `mod` 5 == 0 = print x
            | otherwise = (putStr . (++", ") . show) x


  

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