How to resolve the algorithm Loops/Continue step by step in the Haskell programming language
How to resolve the algorithm Loops/Continue step by step in the Haskell programming language
Table of Contents
Problem Statement
Show the following output using one loop.
Try to achieve the result by forcing the next iteration within the loop upon a specific condition, if your language allows it.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Loops/Continue step by step in the Haskell programming language
The given Haskell code is a simple program that takes input from 1 to 10 and prints each number x
according to the below rules:
- If
x
is divisible by 5, print the number. - Otherwise, print the number followed by a comma and a space
,
.
Detailed Explanation:
-
import Control.Monad (forM)
: This line imports theforM
function from theControl.Monad
module. TheforM
function applies a given function to each element of a list. -
main = forM [1..10] out
: Themain
function is the entry point of the program. It applies theout
function to each number in the list[1..10]
. The[1..10]
list comprehension generates a list of numbers from 1 to 10. -
out x | x
mod5 == 0 = print x
: This line defines theout
function. It takes an integerx
as an argument and has two main cases:- If
x
is divisible by 5 (x
mod5 == 0
), it printsx
using theprint
function. - Otherwise, it continues to the next case.
- If
-
| otherwise = (putStr . (++", ") . show) x
: In this case, it calls theputStr
function, which prints a string to the standard output. The string is constructed using the(++", ") . show)
expression. Let's break it down:show x
: Converts the integerx
into a string representation.(++", ")
: Appends a comma and a space,
to the result ofshow x
.putStr
: Prints the resulting string to the standard output.
So, for each number in the list, the program checks if it's divisible by 5, and if so, prints the number. If not, it prints the number followed by a comma and a space. The output is a list of numbers, separated by commas, with multiples of 5 printed on separate lines.
Example Output:
1, 2, 3, 4, 5
6, 7, 8, 9, 10
Source code in the haskell programming language
import Control.Monad (forM)
main = forM [1..10] out
where
out x | x `mod` 5 == 0 = print x
| otherwise = (putStr . (++", ") . show) x
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