How to resolve the algorithm Loops/Do-while step by step in the C programming language

Published on 7 June 2024 03:52 AM
#C

How to resolve the algorithm Loops/Do-while step by step in the C programming language

Table of Contents

Problem Statement

Start with a value at 0. Loop while value mod 6 is not equal to 0. Each time through the loop, add 1 to the value then print it. The loop must execute at least once.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Loops/Do-while step by step in the C programming language

This C code uses a do-while loop to repeatedly increment the value of val and print it until val is divisible by 6.

  • int val = 0;: This line declares an integer variable named val and initializes it to 0.

  • do { ... } while (condition);: This is a do-while loop. The block of code inside the {} brackets will be executed at least once, even if the condition is false. After the block of code has been executed, the condition is checked. If the condition is true, the loop will continue to execute. If the condition is false, the loop will exit.

  • val++;: This line increments the value of val by 1.

  • printf("%d\n", val);: This line prints the value of val followed by a newline character to the standard output.

  • val % 6 != 0: This is the condition that is checked after each iteration of the loop. It checks if val is not divisible by 6. If val is not divisible by 6, the condition will be true and the loop will continue to execute. If val is divisible by 6, the condition will be false and the loop will exit.

The loop will continue to execute until val is divisible by 6. Once val is divisible by 6, the condition will be false and the loop will exit. The final value of val will be the first multiple of 6 that is greater than or equal to 0.

Source code in the c programming language

int val = 0;
do{
   val++;
   printf("%d\n",val);
}while(val % 6 != 0);


  

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