How to resolve the algorithm Loops/While step by step in the Clojure programming language

Published on 12 May 2024 09:40 PM

#Clojure

How to resolve the algorithm Loops/While step by step in the Clojure programming language

Table of Contents

Problem Statement
Step by Step Solution
Sourcecode

Problem Statement

Start an integer value at 1024. Loop while it is greater than zero. Print the value (with a newline) and divide it by two each time through the loop.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Loops/While step by step in the Clojure programming language

Source code in the clojure programming language

(def i (ref 1024))

(while (> @i 0)
  (println @i)
  (dosync (ref-set i (quot @i 2))))


(loop [i 1024]
  (when (pos? i)
    (println i)
    (recur (quot i 2))))


(doseq [i (take-while pos? (iterate #(quot % 2) 1024))]
  (println i))

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