Step by Step solution about How to resolve the algorithm Loops/While step by step in the Ruby programming language

The Ruby code snippet consists of three parts:

Part 1:

i = 1024
while i > 0 do
  puts i
  i /= 2
end

• i is initialized to 1024.
• It uses a while loop to continuously print i and then divide it by 2 until i becomes less than or equal to 0.
• This loop will print the following output:

1024
512
256
128
64
32
16
8
4
2
1

Part 2:

puts i = 1024
puts i /= 2 while i > 0

• i is reassigned to 1024.
• puts i = 1024 prints 1024.
• puts i /= 2 while i > 0 is a shorthand form of a loop.
  • It first assigns i to 1024 / 2, which is 512, and prints it.
  • Then, it checks if i is greater than 0, which it is.
  • It assigns i to i / 2, which is 256, and prints it.
  • This process continues until i becomes less than or equal to 0.
  • The output will be:

1024
512
256
128
64
32
16
8
4
2
1

Part 3:

i = 1024
until i <= 0 do
  puts i
  i /= 2
end

• i is again initialized to 1024.
• It uses an until loop to repeatedly print i and divide it by 2 until i becomes less than or equal to 0.
• The until loop is similar to the while loop, but it executes the loop body until the condition becomes true.
• The output of this loop will be the same as in Part 1:

1024
512
256
128
64
32
16
8
4
2
1

i = 1024
while i > 0 do
   puts i
   i /= 2
end

puts i = 1024
puts i /= 2 while i > 0

i = 1024
until i <= 0 do
   puts i
   i /= 2
end