How to resolve the algorithm Loops/With multiple ranges step by step in the Ada programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Loops/With multiple ranges step by step in the Ada programming language
Table of Contents
Problem Statement
Some languages allow multiple loop ranges, such as the PL/I example (snippet) below.
Simulate/translate the above PL/I program snippet as best as possible in your language, with particular emphasis on the do loop construct. The do index must be incremented/decremented in the same order shown. If feasible, add commas to the two output numbers (being displayed). Show all output here.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Loops/With multiple ranges step by step in the Ada programming language
Source code in the ada programming language
with Ada.Text_IO; use Ada.Text_IO;
with Ada.Containers.Vectors;
procedure Main is
package int_vector is new Ada.Containers.Vectors
(Index_Type => Natural, Element_Type => Integer);
use int_vector;
summing_values : Vector := Empty_Vector;
prod : Integer := 1;
sum : Integer := 0;
x : Integer := 5;
y : Integer := -5;
z : Integer := -2;
N : Integer;
begin
N := -3;
while N <= 3**3 loop
summing_values.Append (N);
N := N + 3;
end loop;
N := -7;
while N <= 7 loop
summing_values.Append (N);
N := N + x;
end loop;
for I in 555 .. 550 - y loop
summing_values.Append (I);
end loop;
N := 22;
while N >= -28 loop
summing_values.Append (N);
N := N - 3;
end loop;
for I in 1_927 .. 1_939 loop
summing_values.Append (I);
end loop;
N := x;
while N >= y loop
summing_values.Append (N);
N := N + z;
end loop;
for I in 11**x .. 11**x + 1 loop
summing_values.Append (I);
end loop;
for value of summing_values loop
sum := sum + abs (value);
if abs (prod) < 2**27 and then value /= 0 then
prod := prod * value;
end if;
end loop;
Put_Line ("sum = " & sum'Image);
Put_Line ("prod = " & prod'Image);
end Main;
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