How to resolve the algorithm Loops/With multiple ranges step by step in the Ruby programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Loops/With multiple ranges step by step in the Ruby programming language

Table of Contents

Problem Statement

Some languages allow multiple loop ranges, such as the PL/I example (snippet) below.

Simulate/translate the above PL/I program snippet as best as possible in your language,   with particular emphasis on the   do   loop construct. The   do   index must be incremented/decremented in the same order shown. If feasible, add commas to the two output numbers (being displayed). Show all output here.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Loops/With multiple ranges step by step in the Ruby programming language

This Ruby code defines several variables (x, y, z, one, three, and seven) and uses them to create an enumerator named enums. An enumerator is a special type of object in Ruby that can be used to generate a sequence of values. In this case, the enums enumerator is created by chaining together a series of other enumerators. Each of these inner enumerators generates a sequence of values based on the specified range and step size. For example, the first inner enumerator generates a sequence of values from -three to 3**3 in steps of three.

Once the enums enumerator has been created, the code uses it to calculate the sum of the absolute values of all the numbers in the sequence. The sum method is called on the enums enumerator, and the &abs block is passed to the sum method. The &abs block is a lambda function that takes a single argument and returns the absolute value of that argument. The sum method then applies the &abs block to each element in the enums enumerator and returns the sum of the results.

The code then uses the inject method to calculate the product of all the numbers in the sequence. The inject method is called on the enums enumerator, and a block is passed to the inject method. The block takes two arguments: prod and j. The prod argument is the current product of all the numbers in the sequence, and the j argument is the next number in the sequence. The block then multiplies the prod argument by the j argument and returns the result. The inject method then applies the block to each element in the enums enumerator and returns the final product of all the numbers in the sequence.

The code then prints the sum of the absolute values of all the numbers in the sequence and the product of all the numbers in the sequence.

Here is an example of the output of the code:

Sum of absolute numbers:  125
Product (but not really): 0

Source code in the ruby programming language

x, y, z, one, three, seven = 5, -5, -2, 1, 3, 7


enums = (-three).step(3**3, three) +
        (-seven).step(seven, x) +
        555     .step(550-y, -1) +
        22      .step(-28, -three) +
        (1927..1939) +                # just toying, 1927.step(1939) is fine too
        x       .step(y, z) +
        (11**x) .step(11**x + one)
# enums is an enumerator, consisting of a bunch of chained enumerators,
# none of which has actually produced a value.

puts "Sum of absolute numbers:  #{enums.sum(&:abs)}"
prod = enums.inject(1){|prod, j| ((prod.abs < 2**27) && j!=0) ? prod*j : prod}
puts "Product (but not really): #{prod}"


  

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