How to resolve the algorithm Loops/With multiple ranges step by step in the Ruby programming language
How to resolve the algorithm Loops/With multiple ranges step by step in the Ruby programming language
Table of Contents
Problem Statement
Some languages allow multiple loop ranges, such as the PL/I example (snippet) below.
Simulate/translate the above PL/I program snippet as best as possible in your language, with particular emphasis on the do loop construct. The do index must be incremented/decremented in the same order shown. If feasible, add commas to the two output numbers (being displayed). Show all output here.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Loops/With multiple ranges step by step in the Ruby programming language
This Ruby code defines several variables (x
, y
, z
, one
, three
, and seven
) and uses them to create an enumerator named enums
.
An enumerator is a special type of object in Ruby that can be used to generate a sequence of values.
In this case, the enums
enumerator is created by chaining together a series of other enumerators.
Each of these inner enumerators generates a sequence of values based on the specified range and step size.
For example, the first inner enumerator generates a sequence of values from -three
to 3**3
in steps of three
.
Once the enums
enumerator has been created, the code uses it to calculate the sum of the absolute values of all the numbers in the sequence.
The sum
method is called on the enums
enumerator, and the &abs
block is passed to the sum
method.
The &abs
block is a lambda function that takes a single argument and returns the absolute value of that argument.
The sum
method then applies the &abs
block to each element in the enums
enumerator and returns the sum of the results.
The code then uses the inject
method to calculate the product of all the numbers in the sequence.
The inject
method is called on the enums
enumerator, and a block is passed to the inject
method.
The block takes two arguments: prod
and j
.
The prod
argument is the current product of all the numbers in the sequence, and the j
argument is the next number in the sequence.
The block then multiplies the prod
argument by the j
argument and returns the result.
The inject
method then applies the block to each element in the enums
enumerator and returns the final product of all the numbers in the sequence.
The code then prints the sum of the absolute values of all the numbers in the sequence and the product of all the numbers in the sequence.
Here is an example of the output of the code:
Sum of absolute numbers: 125
Product (but not really): 0
Source code in the ruby programming language
x, y, z, one, three, seven = 5, -5, -2, 1, 3, 7
enums = (-three).step(3**3, three) +
(-seven).step(seven, x) +
555 .step(550-y, -1) +
22 .step(-28, -three) +
(1927..1939) + # just toying, 1927.step(1939) is fine too
x .step(y, z) +
(11**x) .step(11**x + one)
# enums is an enumerator, consisting of a bunch of chained enumerators,
# none of which has actually produced a value.
puts "Sum of absolute numbers: #{enums.sum(&:abs)}"
prod = enums.inject(1){|prod, j| ((prod.abs < 2**27) && j!=0) ? prod*j : prod}
puts "Product (but not really): #{prod}"
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