How to resolve the algorithm Ludic numbers step by step in the 11l programming language

Published on 12 May 2024 09:40 PM
#11l

How to resolve the algorithm Ludic numbers step by step in the 11l programming language

Table of Contents

Problem Statement

Ludic numbers   are related to prime numbers as they are generated by a sieve quite like the Sieve of Eratosthenes is used to generate prime numbers. The first ludic number is   1. To generate succeeding ludic numbers create an array of increasing integers starting from   2. (Loop)

Show all triplets of ludic numbers < 250.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Ludic numbers step by step in the 11l programming language

Source code in the 11l programming language

F ludic(nmax = 100000)
   V r = [1]
   V lst = Array(2..nmax)
   L !lst.empty
      r.append(lst[0])
      [Int] newlst
      V step = lst[0]
      L(i) 0 .< lst.len
         I i % step != 0
            newlst.append(lst[i])
      lst = newlst
   R r

V ludics = ludic()
print(‘First 25 ludic primes:’)
print(ludics[0.<25])
print("\nThere are #. ludic numbers <= 1000".format(sum(ludics.filter(l -> l <= 1000).map(l -> 1))))
print("\n2000'th..2005'th ludic primes:")
print(ludics[2000 - 1 .. 2004])
V n = 250
V triplets = ludics.filter(x -> x + 6 < :n &
                           x + 2 C :ludics &
                           x + 6 C :ludics).map(x -> (x, x + 2, x + 6))
print("\nThere are #. triplets less than #.:\n  #.".format(triplets.len, n, triplets))

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