How to resolve the algorithm Magic constant step by step in the Quackery programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Magic constant step by step in the Quackery programming language
Table of Contents
Problem Statement
A magic square is a square grid containing consecutive integers from 1 to N², arranged so that every row, column and diagonal adds up to the same number. That number is a constant. There is no way to create a valid N x N magic square that does not sum to the associated constant. A 3 x 3 magic square always sums to 15. A 4 x 4 magic square always sums to 34. Traditionally, the sequence leaves off terms for n = 0 and n = 1 as the magic squares of order 0 and 1 are trivial; and a term for n = 2 because it is impossible to form a magic square of order 2.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Magic constant step by step in the Quackery programming language
Source code in the quackery programming language
[ 3 + dup 3 ** + 2 / ] is magicconstant ( n --> n )
20 times [ i^ magicconstant echo sp ] cr cr
1000 magicconstant echo cr cr
0 1
[ over magicconstant over > if
[ over 3 + echo cr
10 * ]
dip 1+
[ 10 21 ** ] constant
over = until ]
2drop
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