How to resolve the algorithm Magic squares of odd order step by step in the Fortran programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Magic squares of odd order step by step in the Fortran programming language

Table of Contents

Problem Statement

A magic square is an   NxN   square matrix whose numbers (usually integers) consist of consecutive numbers arranged so that the sum of each row and column,   and   both long (main) diagonals are equal to the same sum (which is called the   magic number   or   magic constant). The numbers are usually (but not always) the first   N2   positive integers. A magic square whose rows and columns add up to a magic number but whose main diagonals do not, is known as a semimagic square.

For any odd   N,   generate a magic square with the integers   1 ──► N,   and show the results here. Optionally, show the magic number.
You should demonstrate the generator by showing at least a magic square for   N = 5.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Magic squares of odd order step by step in the Fortran programming language

Source code in the fortran programming language

program Magic_Square
  implicit none

  integer, parameter :: order = 15
  integer :: i, j
 
  write(*, "(a, i0)") "Magic Square Order: ", order
  write(*, "(a)")     "----------------------"
  do i = 1, order
    do j = 1, order
      write(*, "(i4)", advance = "no") f1(order, i, j)
    end do
    write(*,*)
  end do
  write(*, "(a, i0)") "Magic number = ", f2(order)

contains

integer function f1(n, x, y)
  integer, intent(in) :: n, x, y

  f1 = n * mod(x + y - 1 + n/2, n) + mod(x + 2*y - 2, n) + 1
end function

integer function f2(n)
  integer, intent(in) :: n

  f2 = n * (1 + n * n) / 2
end function
end program


  

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