How to resolve the algorithm Matrix multiplication step by step in the XPL0 programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Matrix multiplication step by step in the XPL0 programming language
Table of Contents
Problem Statement
Multiply two matrices together. They can be of any dimensions, so long as the number of columns of the first matrix is equal to the number of rows of the second matrix.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Matrix multiplication step by step in the XPL0 programming language
Source code in the xpl0 programming language
proc Mat4x1Mul(M, V); \Multiply matrix M times column vector V
real M, \4x4 matrix [M] * [V] -> [V]
V; \column vector
real W(4); \working copy of column vector
int R; \row
[for R:= 0 to 4-1 do
W(R):= M(R,0)*V(0) + M(R,1)*V(1) + M(R,2)*V(2) + M(R,3)*V(3);
for R:= 0 to 4-1 do V(R):= W(R);
];
proc Mat4x4Mul(M, N); \Multiply matrix M times matrix N
real M, N; \4x4 matrices [M] * [N] -> [N]
real W(4,4); \working copy of matrix N
int C; \column
[for C:= 0 to 4-1 do
[W(0,C):= M(0,0)*N(0,C) + M(0,1)*N(1,C) + M(0,2)*N(2,C) + M(0,3)*N(3,C);
W(1,C):= M(1,0)*N(0,C) + M(1,1)*N(1,C) + M(1,2)*N(2,C) + M(1,3)*N(3,C);
W(2,C):= M(2,0)*N(0,C) + M(2,1)*N(1,C) + M(2,2)*N(2,C) + M(2,3)*N(3,C);
W(3,C):= M(3,0)*N(0,C) + M(3,1)*N(1,C) + M(3,2)*N(2,C) + M(3,3)*N(3,C);
];
for C:= 0 to 4-1 do
[N(0,C):= W(0,C);
N(1,C):= W(1,C);
N(2,C):= W(2,C);
N(3,C):= W(3,C);
];
];
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