Step by Step solution about How to resolve the algorithm McNuggets problem step by step in the Kotlin programming language

The provided Kotlin code determines the maximum non-McNuggets number up to a certain limit. A McNuggets number is a number that can be formed using only 6, 9, and 20 as factors.

Here's how the code works:

1. It initializes a Boolean array sv of size limit + 1, where limit is the maximum number to check. Initially, all elements in sv are set to false.

2. It iterates through three nested loops to populate sv. For each combination of factors (6, 9, and 20), it checks if the resulting number (e.g., 6, 9, 12, 15, ...) is within the limit. If it is, it sets the corresponding element in sv to true.

3. After populating sv, it starts another loop that iterates in reverse order from limit down to 0.

4. For each number i in the reverse loop, it checks if sv[i] is false. If it is, it means that i cannot be formed using the factors 6, 9, and 20. Therefore, it prints that i is the maximum non-McNuggets number and terminates the program.

5. If the loop completes without finding a non-McNugget number, it means that all numbers up to limit can be formed using the given factors. In that case, it doesn't print anything.

In the main function, it calls mcnugget(100) to find the maximum non-McNuggets number up to 100. The output will be "Maximum non-McNuggets number is 43".

// Version 1.2.71

fun mcnugget(limit: Int) {
    val sv = BooleanArray(limit + 1)  // all false by default
    for (s in 0..limit step 6)
        for (n in s..limit step 9)
            for (t in n..limit step 20) sv[t] = true

    for (i in limit downTo 0) {
        if (!sv[i]) {
            println("Maximum non-McNuggets number is $i")
            return
        }
    }
}

fun main(args: Array<String>) {
    mcnugget(100)
}