Step by Step solution about How to resolve the algorithm Memory allocation step by step in the Haskell programming language

bytealloc

This function allocates memory in the C heap.

1. mallocBytes 100: Allocates 100 bytes in the C heap and returns a pointer to the allocated memory.
2. free a0: Frees the memory allocated by mallocBytes.
3. allocaBytes 100 $ \a -> poke (a::Ptr Word32) 0: Allocates 100 bytes in the C stack and passes the pointer to the allocated memory to the closure. The closure writes a zero to the first word of the allocated memory. The closure is automatically freed when it finishes executing, freeing the memory allocated by allocaBytes.

typedalloc

This function also allocates memory in the C heap, but it uses the malloc and free functions from the Foreign module, which are specifically designed for allocating and freeing memory of a specific type.

1. w <- malloc: Allocates memory for a single Word32 value in the C heap and returns a pointer to the allocated memory.
2. poke w (100 :: Word32): Writes the value 100 to the memory pointed to by w.
3. free w: Frees the memory allocated by malloc.
4. alloca $ \a -> poke a (100 :: Word32): Allocates memory for a single Word32 value in the C stack and passes the pointer to the allocated memory to the closure. The closure writes the value 100 to the memory pointed to by a. The closure is automatically freed when it finishes executing, freeing the memory allocated by alloca.

import Foreign

bytealloc :: IO ()
bytealloc = do
  a0 <- mallocBytes 100 -- Allocate 100 bytes
  free a0 -- Free them again
  allocaBytes 100 $ \a -> -- Allocate 100 bytes; automatically
                          -- freed when closure finishes
    poke (a::Ptr Word32) 0


import Foreign

typedalloc :: IO ()
typedalloc = do
  w <- malloc
  poke w (100 :: Word32)
  free w
  alloca $ \a -> poke a (100 :: Word32)