How to resolve the algorithm Mertens function step by step in the Cowgol programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Mertens function step by step in the Cowgol programming language
Table of Contents
Problem Statement
The Mertens function M(x) is the count of square-free integers up to x that have an even number of prime factors, minus the count of those that have an odd number. It is an extension of the Möbius function. Given the Möbius function μ(n), the Mertens function M(x) is the sum of the Möbius numbers from n == 1 through n == x.
This is not code golf. The stackexchange link is provided as an algorithm reference, not as a guide.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Mertens function step by step in the Cowgol programming language
Source code in the cowgol programming language
include "cowgol.coh";
const MAX := 1000;
# Table output
sub printtab(n: int8) is
if n<0 then
print_char('-');
n := -n;
else
print_char(' ');
end if;
print_char(n as uint8 + '0');
print_char(' ');
end sub;
# Generate Merten numbers
var M: int8[MAX+1];
M[0] := 0;
M[1] := 1;
var n: @indexof M := 2;
while n < @sizeof M loop
M[n] := 1;
var k: @indexof M := 2;
while k <= n loop
M[n] := M[n] - M[n/k];
k := k + 1;
end loop;
n := n + 1;
end loop;
# Find zeroes and crossings
var zero: uint8 := 0;
var cross: uint8 := 0;
n := 1;
while n < @sizeof M loop
if M[n] == 0 then
zero := zero + 1;
if M[n-1] != 0 then
cross := cross + 1;
end if;
end if;
n := n + 1;
end loop;
# Print table
print("The first 99 Mertens numbers are:\n");
print(" ");
n := 1;
var col: uint8 := 9;
while n < 100 loop
printtab(M[n]);
col := col - 1;
if col == 0 then
print_nl();
col := 10;
end if;
n := n + 1;
end loop;
print("M(n) is zero "); print_i8(zero); print(" times\n");
print("M(n) crosses zero "); print_i8(cross); print(" times\n");
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