Step by Step solution about How to resolve the algorithm Minimum multiple of m where digital sum equals m step by step in the Go programming language

The provided Go program calculates and displays a table of the smallest integer multiples (m) for which the digit sum of the product m*n equals n, for n ranging from 1 to 70. Here's a detailed explanation:

1. The program imports the rcu package, which provides various utility functions, including DigitSum() and PrintTable().

2. The main() function is the entry point of the program.

3. It initializes an empty slice of integers, res, to store the results.

4. The program enters a for loop that iterates through n values from 1 to 70.

5. For each n, it initializes m to 1.

6. Inside a nested for loop, the program repeatedly increments m until it finds a value for which the digit sum of the product m*n equals n. This is determined by calling rcu.DigitSum(m*n, 10). The DigitSum() function calculates the sum of the digits of a given integer in a specified base (10 in this case).

7. Once such an m is found for the current n, it is appended to the res slice.

8. After processing all values of n, the program calls rcu.PrintTable() to display the results in a tabular format. The arguments provided to PrintTable() specify the slice of values to print, the number of columns to use (7), the cell width (10), and whether to print a header (true).

In summary, this program calculates and displays a table of the smallest integer multiples m for which the digit sum of m*n equals n, for n ranging from 1 to 70.

package main

import "rcu"

func main() {
    var res []int
    for n := 1; n <= 70; n++ {
        m := 1
        for rcu.DigitSum(m*n, 10) != n {
            m++
        }
        res = append(res, m)
    }
    rcu.PrintTable(res, 7, 10, true)
}