How to resolve the algorithm Minimum multiple of m where digital sum equals m step by step in the jq programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Minimum multiple of m where digital sum equals m step by step in the jq programming language
Table of Contents
Problem Statement
Generate the sequence a(n) when each element is the minimum integer multiple m such that the digit sum of n times m is equal to n.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Minimum multiple of m where digital sum equals m step by step in the jq programming language
Source code in the jq programming language
1 | until((. * $n) | digitSum == $n; . + 1)
def minimum_integer_multiple:
def digitSum:
def add(s): reduce s as $_ (0; .+$_);
add(tostring | explode[] | . - 48);
. as $n
| 1 | until((. * $n) | digitSum == $n; . + 1);
# This function assumes that nan can be taken as the eos marker
def nwise(stream; $n):
foreach (stream, nan) as $x ([];
if length == $n then [$x] else . + [$x] end)
| if (.[-1] | isnan) and length>1 then .[:-1]
elif length == $n then .
else empty
end;
def lpad($len): tostring | ($len - length) as $l | (" " * $l)[:$l] + .;
nwise(
range(1; 71) | minimum_integer_multiple;
10)
| map(lpad(9)) | join(" ")
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