How to resolve the algorithm Monads/List monad step by step in the OCaml programming language

Published on 12 May 2024 09:40 PM
#Ocaml

How to resolve the algorithm Monads/List monad step by step in the OCaml programming language

Table of Contents

Problem Statement

A Monad is a combination of a data-type with two helper functions written for that type. The data-type can be of any kind which can contain values of some other type – common examples are lists, records, sum-types, even functions or IO streams. The two special functions, mathematically known as eta and mu, but usually given more expressive names like 'pure', 'return', or 'yield' and 'bind', abstract away some boilerplate needed for pipe-lining or enchaining sequences of computations on values held in the containing data-type. The bind operator in the List monad enchains computations which return their values wrapped in lists. One application of this is the representation of indeterminacy, with returned lists representing a set of possible values. An empty list can be returned to express incomputability, or computational failure. A sequence of two list monad computations (enchained with the use of bind) can be understood as the computation of a cartesian product. The natural implementation of bind for the List monad is a composition of concat and map, which, used with a function which returns its value as a (possibly empty) list, provides for filtering in addition to transformation or mapping.

Demonstrate in your programming language the following:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Monads/List monad step by step in the OCaml programming language

Source code in the ocaml programming language

let bind : 'a list -> ('a -> 'b list) -> 'b list =
  fun l f -> List.flatten (List.map f l)

let return x = [x]


let (>>) = bind (* operator for inline binding *)
let (let*) = bind (* let pruning for easy bind *)

let print_str_list l =
    Format.printf "[%a]" (fun fmt -> Format.pp_print_list Format.pp_print_string fmt) l


let incr x = return (x+1)
let hex x = return (Format.sprintf "%#x" x)

(* Version 1 : With explicit calls *)
let () =
  let l = bind (bind (List.init 5 (fun x -> x)) incr) hex in
  print_str_list l

(* Version 2 : With >> operator *)
let () =
  let l = List.init 5 (fun x -> x) >> incr >> hex in
  print_str_list l

(* Version 3 : With let pruning *)
let () =
  let l =
    let* x = List.init 5 (fun x -> x) in
    let* y = incr x in hex y
  in print_str_list l


(* Version 1 : with explicit calls *)
let pythegorean_triple n =
  let x = List.init n (fun x -> x) in
  let y = List.init n (fun x -> x) in
  let z = List.init n (fun x -> x) in
  bind x (fun x ->
    bind y (fun y ->
      bind z (fun z ->
        if x*x + y*y = z*z then return (x,y,z) else []
  )))

(* Version 2 : with >> operator *)
let pythegorean_triple n =
  List.init n (fun x -> x) >> fun x ->
    List.init n (fun x -> x) >> fun y ->
      List.init n (fun x -> x) >> fun z ->
        if x*x + y*y = z*z then return (x,y,z) else []

(* Version 3 : with let pruning *)
let pythegorean_triple n =
  let* x = List.init n (fun x -> x) in
  let* y = List.init n (fun x -> x) in
  let* z = List.init n (fun x -> x) in
  if x*x + y*y = z*z then return (x,y,z) else []

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