How to resolve the algorithm Multifactorial step by step in the Dart programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Multifactorial step by step in the Dart programming language

Table of Contents

Problem Statement

The factorial of a number, written as

n !

{\displaystyle n!}

, is defined as

n !

n ( n − 1 ) ( n − 2 ) . . . ( 2 ) ( 1 )

{\displaystyle n!=n(n-1)(n-2)...(2)(1)}

. Multifactorials generalize factorials as follows: In all cases, the terms in the products are positive integers. If we define the degree of the multifactorial as the difference in successive terms that are multiplied together for a multifactorial (the number of exclamation marks), then the task is twofold:

Note: The wikipedia entry on multifactorials gives a different formula. This task uses the Wolfram mathworld definition.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Multifactorial step by step in the Dart programming language

Source code in the dart programming language

main()
{
  int n=5,d=3;
int z= fact(n,d);
print('$n factorial of degree $d is $z');
for(var j=1;j<=5;j++)
{
  print('first 10 numbers of degree $j :');
  for(var i=1;i<=10;i++)
  {   
    int z=fact(i,j);
 print('$z'); 
}
  print('\n');
}
}

int fact(int a,int b)
{
  
  if(a<=b||a==0)
    return a;
  if(a>1)
    return a*fact((a-b),b);
}


  

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