How to resolve the algorithm Multifactorial step by step in the Dart programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Multifactorial step by step in the Dart programming language
Table of Contents
Problem Statement
The factorial of a number, written as
n !
{\displaystyle n!}
, is defined as
n !
n ( n − 1 ) ( n − 2 ) . . . ( 2 ) ( 1 )
{\displaystyle n!=n(n-1)(n-2)...(2)(1)}
. Multifactorials generalize factorials as follows: In all cases, the terms in the products are positive integers. If we define the degree of the multifactorial as the difference in successive terms that are multiplied together for a multifactorial (the number of exclamation marks), then the task is twofold:
Note: The wikipedia entry on multifactorials gives a different formula. This task uses the Wolfram mathworld definition.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Multifactorial step by step in the Dart programming language
Source code in the dart programming language
main()
{
int n=5,d=3;
int z= fact(n,d);
print('$n factorial of degree $d is $z');
for(var j=1;j<=5;j++)
{
print('first 10 numbers of degree $j :');
for(var i=1;i<=10;i++)
{
int z=fact(i,j);
print('$z');
}
print('\n');
}
}
int fact(int a,int b)
{
if(a<=b||a==0)
return a;
if(a>1)
return a*fact((a-b),b);
}
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