How to resolve the algorithm Multifactorial step by step in the Rust programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Multifactorial step by step in the Rust programming language

Table of Contents

Problem Statement

The factorial of a number, written as

n !

{\displaystyle n!}

, is defined as

n !

n ( n − 1 ) ( n − 2 ) . . . ( 2 ) ( 1 )

{\displaystyle n!=n(n-1)(n-2)...(2)(1)}

. Multifactorials generalize factorials as follows: In all cases, the terms in the products are positive integers. If we define the degree of the multifactorial as the difference in successive terms that are multiplied together for a multifactorial (the number of exclamation marks), then the task is twofold:

Note: The wikipedia entry on multifactorials gives a different formula. This task uses the Wolfram mathworld definition.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Multifactorial step by step in the Rust programming language

Source code in the rust programming language

fn multifactorial(n: i32, deg: i32) -> i32 {
	if n < 1 {
		1
	} else {
		n * multifactorial(n - deg, deg)
	}
}

fn main() {
	for i in 1..6 {
		for j in 1..11 {
			print!("{} ", multifactorial(j, i));
		}
	println!("");
	}
}


  

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