How to resolve the algorithm Multiple regression step by step in the Ruby programming language
How to resolve the algorithm Multiple regression step by step in the Ruby programming language
Table of Contents
Problem Statement
Given a set of data vectors in the following format: Compute the vector
β
{
β
1
,
β
2
, . . . ,
β
k
}
{\displaystyle \beta ={\beta _{1},\beta _{2},...,\beta _{k}}}
using ordinary least squares regression using the following equation: You can assume y is given to you as a vector (a one-dimensional array), and X is given to you as a two-dimensional array (i.e. matrix).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Multiple regression step by step in the Ruby programming language
The Ruby code snippet you provided demonstrates the implementation of linear regression to determine the coefficients of a linear equation that best fits a given set of data points. It takes in two arrays: y
representing the dependent variable and x
representing the independent variables. Then, the code uses the Matrix
library to perform matrix operations and compute the regression coefficients.
A breakdown of the code:
require 'matrix'
: This line includes the 'Matrix' library, which provides classes and methods for working with matrices in Ruby.def regression_coefficients y, x
: This line defines a method calledregression_coefficients
that takes two parameters:y
(an array of dependent variable values) andx
(an array of independent variable values).y = Matrix.column_vector y.map { |i| i.to_f }
: Here, the dependent variable values (y
) are converted into a column vector of typeMatrix::ColumnVector
using thecolumn_vector
method. This is done by mapping each element of they
array to its floating-point representation usingto_f
.x = Matrix.columns x.map { |xi| xi.map { |i| i.to_f }}
: The independent variable values (x
) are converted into a matrix of typeMatrix
using thecolumns
method. This is achieved by first mapping each row of thex
array (xi
represents each row) to a row vector, and then mapping each element of the row vector to its floating-point representation usingto_f
.(x.t * x).inverse * x.t * y
: This line calculates the regression coefficients using matrix operations.x.t
: Transposes thex
matrix.(x.t * x)
: Multiplies the transposedx
matrix by itself, effectively calculating the covariance matrix.(x.t * x).inverse
: Inverts the covariance matrix.(x.t * x).inverse * x.t
: Multiplies the inverse of the covariance matrix by the transposedx
matrix.(x.t * x).inverse * x.t * y
: Finally, multiplies the result by the column vectory
, which contains the dependent variable values. The resulting matrix represents the regression coefficients.
- The code demonstrates the usage of the
regression_coefficients
method by providing two examples:- The first example computes regression coefficients for a set of data points with one independent variable.
- The second example computes regression coefficients for a set of data points with two independent variables.
In summary, this code defines a method for linear regression that calculates regression coefficients based on a given set of data points. It utilizes the 'Matrix' library for matrix operations, and demonstrates the method's usage with two examples of linear regression.
Source code in the ruby programming language
require 'matrix'
def regression_coefficients y, x
y = Matrix.column_vector y.map { |i| i.to_f }
x = Matrix.columns x.map { |xi| xi.map { |i| i.to_f }}
(x.t * x).inverse * x.t * y
end
puts regression_coefficients([1, 2, 3, 4, 5], [ [2, 1, 3, 4, 5] ])
puts regression_coefficients([3,4,5], [ [1,2,1], [1,1,2] ])
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