Step by Step solution about How to resolve the algorithm Munchausen numbers step by step in the Julia programming language

The provided Julia code snippet is a one-liner that generates a list of numbers from 1 to 5000 and filters out the numbers that are equal to the sum of their digits raised to the power of their respective digits.

1. The digits function takes a number as input and returns a vector of its individual digits.
2. The ^ operator is used to raise each digit to the power of itself.
3. The sum function is used to add up the results of the exponentiation.
4. The == operator is used to compare the sum of the exponentiated digits to the original number.
5. The if statement is used to filter out the numbers that do not satisfy the condition.
6. The filtered list is then passed to the println function to print it to the console.

Here is a breakdown of the code:

# Generate a list of numbers from 1 to 5000
numbers = 1:5000

# Filter out the numbers that are not equal to the sum of their digits raised to the power of their respective digits
filtered_numbers = [n for n in numbers if sum(d^d for d in digits(n)) == n]

# Print the filtered list to the console
println(filtered_numbers)

println([n for n = 1:5000 if sum(d^d for d in digits(n)) == n])