How to resolve the algorithm Mutex step by step in the Oforth programming language
How to resolve the algorithm Mutex step by step in the Oforth programming language
Table of Contents
Problem Statement
A mutex (abbreviated Mutually Exclusive access) is a synchronization object, a variant of semaphore with k=1. A mutex is said to be seized by a task decreasing k. It is released when the task restores k. Mutexes are typically used to protect a shared resource from concurrent access. A task seizes (or acquires) the mutex, then accesses the resource, and after that releases the mutex. A mutex is a low-level synchronization primitive exposed to deadlocking. A deadlock can occur with just two tasks and two mutexes (if each task attempts to acquire both mutexes, but in the opposite order). Entering the deadlock is usually aggravated by a race condition state, which leads to sporadic hangups, which are very difficult to track down.
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Step by Step solution about How to resolve the algorithm Mutex step by step in the Oforth programming language
Source code in the oforth programming language
import: parallel
: job(mut)
mut receive drop
"I get the mutex !" .
2000 sleep
"Now I release the mutex" println
1 mut send drop ;
: mymutex
| mut |
Channel new dup send(1) drop ->mut
10 #[ #[ mut job ] & ] times ;
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