How to resolve the algorithm Non-continuous subsequences step by step in the Bracmat programming language
How to resolve the algorithm Non-continuous subsequences step by step in the Bracmat programming language
Table of Contents
Problem Statement
Consider some sequence of elements. (It differs from a mere set of elements by having an ordering among members.) A subsequence contains some subset of the elements of this sequence, in the same order. A continuous subsequence is one in which no elements are missing between the first and last elements of the subsequence. Note: Subsequences are defined structurally, not by their contents. So a sequence a,b,c,d will always have the same subsequences and continuous subsequences, no matter which values are substituted; it may even be the same value.
Task: Find all non-continuous subsequences for a given sequence.
For the sequence 1,2,3,4, there are five non-continuous subsequences, namely:
There are different ways to calculate those subsequences. Demonstrate algorithm(s) that are natural for the language.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Non-continuous subsequences step by step in the Bracmat programming language
Source code in the bracmat programming language
( ( noncontinuous
= sub
. ( sub
= su a nc
. !arg:(?su.?nc)
& !su
: %
%?a
( %:[%(sub$(!sjt.!nc !a))
| ?
& !nc:~
& out$(!nc !a)
& ~
)
)
& sub$(dummy !arg.)
|
)
& noncontinuous$(e r n i t)
);
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