How to resolve the algorithm Non-continuous subsequences step by step in the Julia programming language
How to resolve the algorithm Non-continuous subsequences step by step in the Julia programming language
Table of Contents
Problem Statement
Consider some sequence of elements. (It differs from a mere set of elements by having an ordering among members.) A subsequence contains some subset of the elements of this sequence, in the same order. A continuous subsequence is one in which no elements are missing between the first and last elements of the subsequence. Note: Subsequences are defined structurally, not by their contents. So a sequence a,b,c,d will always have the same subsequences and continuous subsequences, no matter which values are substituted; it may even be the same value.
Task: Find all non-continuous subsequences for a given sequence.
For the sequence 1,2,3,4, there are five non-continuous subsequences, namely:
There are different ways to calculate those subsequences. Demonstrate algorithm(s) that are natural for the language.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Non-continuous subsequences step by step in the Julia programming language
Code Overview: The provided code generates and explores non-consecutive subsequences (NC subsequences) of a given length. A non-consecutive subsequence is a subsequence where no two consecutive elements are adjacent in the original sequence.
NCSubSeq:
The NCSubSeq
struct represents a non-consecutive subsequence. It stores the length (n
) of the original sequence from which subsequences will be generated.
NCSubState:
The NCSubState
mutable struct represents the state of an iterator over NC subsequences. It holds two fields:
m
: An integer representing the current subsequence being generated.m2s
: A function that maps an integerm
to the corresponding NC subsequence.
Iterator Implementation:
The iterate
method for NCSubSeq
implements a stateful iterator. It generates NC subsequences in ascending order until reaching the end of the sequence. The iterator maintains the NCSubState
and updates it for each subsequence generation.
iscontseq Function:
iscontseq
checks if a given integer n
represents a non-consecutive subsequence. It does so by ensuring that the count of zeros in the binary representation of n
matches the sum of leading and trailing zeros.
makeint2seq Function:
makeint2seq
creates a closure function that maps an integer m
to its corresponding NC subsequence. It calculates the binary digits of m
with a fixed number of digits (based on the input argument n
). The subsequence is then extracted by selecting the indices where the binary digits are 1.
Example Usage: The code demonstrates:
- Generating NC subsequences for a 4-item sequence and printing them.
- Generating the first and last 10 NC subsequences of the string "Rosetta".
- Generating the first and last 10 NC subsequences of integer sequences of varying lengths.
Additional Features:
- The
Base.IteratorSize
andBase.length
methods are implemented forNCSubSeq
to indicate that it can be used in for loops and its length can be obtained. - The
@sprintf
and@printf
macros are used for string formatting.
Source code in the julia programming language
using Printf, IterTools
import Base.IteratorSize, Base.iterate, Base.length
iscontseq(n::Integer) = count_zeros(n) == leading_zeros(n) + trailing_zeros(n)
iscontseq(n::BigInt) = !ismatch(r"0", rstrip(bin(n), '0'))
function makeint2seq(n::Integer)
idex = collect(1:n)
function int2seq(m::Integer)
d = digits(m, base=2, pad=n)
idex[d .== 1]
end
return int2seq
end
struct NCSubSeq{T<:Integer}
n::T
end
mutable struct NCSubState{T<:Integer}
m::T
m2s::Function
end
Base.IteratorSize(::NCSubSeq) = Base.HasLength()
Base.length(a::NCSubSeq) = 2 ^ a.n - a.n * (a.n + 1) ÷ 2 - 1
function Base.iterate(a::NCSubSeq, as::NCSubState=NCSubState(5, makeint2seq(a.n)))
if 2 ^ a.n - 3 < as.m
return nothing
end
s = as.m2s(as.m)
as.m += 1
while iscontseq(as.m)
as.m += 1
end
return (s, as)
end
n = 4
println("Testing NCSubSeq for ", n, " items:\n ", join(NCSubSeq(n), " "))
s = "Rosetta"
cs = split(s, "")
m = 10
n = length(NCSubSeq(length(cs))) - m
println("\nThe first and last ", m, " NC sub-sequences of \"", s, "\":")
for (i, a) in enumerate(NCSubSeq(length(s)))
i <= m || n < i || continue
println(@sprintf "%6d %s" i join(cs[a], ""))
i == m || continue
println(" .. ......")
end
println("\nThe first and last ", m, " NC sub-sequences of \"", s, "\"")
for x in IterTools.Iterators.flatten([1:10; 20:10:40; big.(50:50:200)])
@printf "%7d → %d\n" x length(NCSubSeq(x))
end
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