Step by Step solution about How to resolve the algorithm N'th step by step in the Python programming language

Both code snippets provided solve the same problem: generating ordinal numbers in English for a given input number. Here's a detailed explanation of both code snippets:

Code Snippet 1:

_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']

def nth(n):
   return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')

if __name__ == '__main__':
   for j in range(0,1001, 250):
       print(' '.join(nth(i) for i in list(range(j, j+25))))

Explanation:

• It uses a list _suffix to store the suffixes for different cases, such as "th," "st," "nd," etc.
• The nth function takes an integer n and generates the ordinal number by combining the number with the appropriate suffix from _suffix.
• It handles special cases where the number ends in 11, 12, or 13 and adds "th" instead of the usual suffix.
• In the if __name__ == '__main__' block, it iterates through a range of numbers in steps of 250 (starting from 0) and prints the ordinal numbers for each number in that range, separated by spaces.

Code Snippet 2:

def ord(n):
   try:
       s = ['st', 'nd', 'rd'][(n-1)%10]
       if (n-10)%100//10:
           return str(n)+s
   except IndexError:
       pass
   return str(n)+'th'

if __name__ == '__main__':
   print(*(ord(n) for n in range(26)))
   print(*(ord(n) for n in range(250,266)))
   print(*(ord(n) for n in range(1000,1026)))

Explanation:

• This code defines an ord function that takes an integer n and generates the ordinal number.
• It uses a try-except block to handle different cases:
  • For numbers ending in 1, 2, or 3, it uses the suffixes "st," "nd," and "rd" from the list s.
  • For numbers ending in 11, 12, or 13, it adds "th" as the suffix.
  • For all other numbers, it adds "th" as the suffix.
• In the if __name__ == '__main__' block, it prints the ordinal numbers for a range of numbers (26, 250-266, and 1000-1026).

_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']

def nth(n):
    return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')

if __name__ == '__main__':
    for j in range(0,1001, 250):
        print(' '.join(nth(i) for i in list(range(j, j+25))))


#!/usr/bin/env python3

def ord(n):
    try:
        s = ['st', 'nd', 'rd'][(n-1)%10]
        if (n-10)%100//10:
            return str(n)+s
    except IndexError:
        pass
    return str(n)+'th'

if __name__ == '__main__':
    print(*(ord(n) for n in range(26)))
    print(*(ord(n) for n in range(250,266)))
    print(*(ord(n) for n in range(1000,1026)))