How to resolve the algorithm Number names step by step in the Ada programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Number names step by step in the Ada programming language
Table of Contents
Problem Statement
Show how to spell out a number in English. You can use a preexisting implementation or roll your own, but you should support inputs up to at least one million (or the maximum value of your language's default bounded integer type, if that's less). Support for inputs other than positive integers (like zero, negative integers, and floating-point numbers) is optional.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Number names step by step in the Ada programming language
Source code in the ada programming language
with Ada.Text_IO;
procedure Integers_In_English is
type Spellable is range -999_999_999_999_999_999..999_999_999_999_999_999;
function Spell (N : Spellable) return String is
function Twenty (N : Spellable) return String is
begin
case N mod 20 is
when 0 => return "zero";
when 1 => return "one";
when 2 => return "two";
when 3 => return "three";
when 4 => return "four";
when 5 => return "five";
when 6 => return "six";
when 7 => return "seven";
when 8 => return "eight";
when 9 => return "nine";
when 10 => return "ten";
when 11 => return "eleven";
when 12 => return "twelve";
when 13 => return "thirteen";
when 14 => return "fourteen";
when 15 => return "fifteen";
when 16 => return "sixteen";
when 17 => return "seventeen";
when 18 => return "eighteen";
when others => return "nineteen";
end case;
end Twenty;
function Decade (N : Spellable) return String is
begin
case N mod 10 is
when 2 => return "twenty";
when 3 => return "thirty";
when 4 => return "forty";
when 5 => return "fifty";
when 6 => return "sixty";
when 7 => return "seventy";
when 8 => return "eighty";
when others => return "ninety";
end case;
end Decade;
function Hundred (N : Spellable) return String is
begin
if N < 20 then
return Twenty (N);
elsif 0 = N mod 10 then
return Decade (N / 10 mod 10);
else
return Decade (N / 10) & '-' & Twenty (N mod 10);
end if;
end Hundred;
function Thousand (N : Spellable) return String is
begin
if N < 100 then
return Hundred (N);
elsif 0 = N mod 100 then
return Twenty (N / 100) & " hundred";
else
return Twenty (N / 100) & " hundred and " & Hundred (N mod 100);
end if;
end Thousand;
function Triplet
( N : Spellable;
Order : Spellable;
Name : String;
Rest : not null access function (N : Spellable) return String
) return String is
High : Spellable := N / Order;
Low : Spellable := N mod Order;
begin
if High = 0 then
return Rest (Low);
elsif Low = 0 then
return Thousand (High) & ' ' & Name;
else
return Thousand (High) & ' ' & Name & ", " & Rest (Low);
end if;
end Triplet;
function Million (N : Spellable) return String is
begin
return Triplet (N, 10**3, "thousand", Thousand'Access);
end Million;
function Milliard (N : Spellable) return String is
begin
return Triplet (N, 10**6, "million", Million'Access);
end Milliard;
function Billion (N : Spellable) return String is
begin
return Triplet (N, 10**9, "milliard", Milliard'Access);
end Billion;
function Billiard (N : Spellable) return String is
begin
return Triplet (N, 10**12, "billion", Billion'Access);
end Billiard;
begin
if N < 0 then
return "negative " & Spell(-N);
else
return Triplet (N, 10**15, "billiard", Billiard'Access);
end if;
end Spell;
procedure Spell_And_Print(N: Spellable) is
Number: constant String := Spellable'Image(N);
Spaces: constant String(1 .. 20) := (others => ' '); -- 20 * ' '
begin
Ada.Text_IO.Put_Line(Spaces(Spaces'First .. Spaces'Last-Number'Length)
& Number & ' ' & Spell(N));
end Spell_And_Print;
Samples: constant array (Natural range <>) of Spellable
:= (99, 300, 310, 1_501, 12_609, 512_609, 43_112_609, 77_000_112_609,
2_000_000_000_100, 999_999_999_999_999_999,
0, -99, -1501, -77_000_112_609, -123_456_789_987_654_321);
begin
for I in Samples'Range loop
Spell_And_Print(Samples(I));
end loop;
end Integers_In_English;
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