Step by Step solution about How to resolve the algorithm Numbers which are the cube roots of the product of their proper divisors step by step in the Go programming language

The code snippet provided is a Go program that finds the first 50,000 numbers that have 1 or 8 divisors and prints them in a table. It uses a function called divisorCount to calculate the number of divisors for a given integer n.

The divisorCount function works by iterating over all the integers from 1 to the square root of n. For each integer i, it checks if n is divisible by i. If it is, then i and n/i are both divisors of n. The function keeps a count of the number of divisors and returns it at the end.

The main function starts by initializing an empty slice called numbers50. Then, it enters a loop that iterates over all the integers starting from 1. For each integer n, it calls the divisorCount function to calculate the number of divisors for n. If n has 1 or 8 divisors, then it is added to the numbers50 slice and the count is incremented.

Once the count reaches 50, the numbers50 slice is printed in a table using the PrintTable function from the rcu package. The PrintTable function takes a slice of integers, the number of columns to print, and the number of digits to pad each number with. It prints the numbers in a table format, with each number right-aligned and padded with zeros.

The main function continues iterating over the integers until the count reaches 50,000. At that point, it prints the 500th, 5,000th, and 50,000th numbers that have 1 or 8 divisors.

The output of the program is a table of the first 50 numbers that have 1 or 8 divisors, followed by the 500th, 5,000th, and 50,000th numbers that have 1 or 8 divisors.

package main

import (
    "fmt"
    "math"
    "rcu"
)

func divisorCount(n int) int {
    k := 1
    if n%2 == 1 {
        k = 2
    }
    count := 0
    sqrt := int(math.Sqrt(float64(n)))
    for i := 1; i <= sqrt; i += k {
        if n%i == 0 {
            count++
            j := n / i
            if j != i {
                count++
            }
        }
    }
    return count
}

func main() {
    var numbers50 []int
    count := 0
    for n := 1; count < 50000; n++ {
        dc := divisorCount(n)
        if n == 1 || dc == 8 {
            count++
            if count <= 50 {
                numbers50 = append(numbers50, n)
                if count == 50 {
                    rcu.PrintTable(numbers50, 10, 3, false)
                }
            } else if count == 500 {
                fmt.Printf("\n500th   : %s", rcu.Commatize(n))
            } else if count == 5000 {
                fmt.Printf("\n5,000th : %s", rcu.Commatize(n))
            } else if count == 50000 {
                fmt.Printf("\n50,000th: %s\n", rcu.Commatize(n))
            }
        }
    }
}