How to resolve the algorithm Old Russian measure of length step by step in the Frink programming language

Published on 12 May 2024 09:40 PM
#Frink

How to resolve the algorithm Old Russian measure of length step by step in the Frink programming language

Table of Contents

Problem Statement

Write a program to perform a conversion of the old Russian measures of length to the metric system   (and vice versa).

It is an example of a linear transformation of several variables.

The program should accept a single value in a selected unit of measurement, and convert and return it to the other units: vershoks, arshins, sazhens, versts, meters, centimeters and kilometers.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Old Russian measure of length step by step in the Frink programming language

Source code in the frink programming language

arshin  := (2 + 1/3) ft
vershok := 1/16 arshin
sazhen  := 3 arshin
verst   := 1500 arshin
versta  := verst

do
{
   valstr = input["Enter unit of measure: ", "1 arshin"]
   val = eval[valstr]
   if ! (val conforms length)
      println["$valstr is not a unit of length."]
} until val conforms length

println["$valstr = "]
println["     " + (val -> "arshin")]
println["     " + (val -> "vershok")]
println["     " + (val -> "sazhen")]
println["     " + (val -> "verst")]
println["     " + (val -> "feet")]
println["     " + (val -> "meters")]
println["     " + (val -> "centimeters")]
println["     " + (val -> "kilometers")]

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