Step by Step solution about How to resolve the algorithm One-dimensional cellular automata step by step in the C# programming language

This program simulates a one-dimensional cellular automata. Specifically, it simulates a 20-cell automaton with the rule 90 (also known as 170 in Wolfram code, since 90 in base 10 is 170 in base 2). A cellular automaton is a collection of cells that can be in one of a finite number of states, usually 0 or 1. The program starts with a 20-cell automaton with the following initial state:

- - - - - - - - - - - - - - - - -

The program then iterates through 10 generations of the automaton, applying the rule 90 to each cell at each generation. The rule 90 is defined as follows: a cell will be 1 in the next generation if and only if its two neighbors are different. This means that a cell will be 0 in the next generation if and only if its two neighbors are the same.

The program prints the state of the automaton after each generation. The output of the program is as follows:

- - - - - - - - - - - - - - - - -
# - - # - # - - # - - # - - # - -
# # - # - # - # - # - # - # - # -
# - # - # - # - # - # - # - # - #
# # - # - # - # - # - # - # - # -
# - # - # - # - # - # - # - # - #
# # - # - # - # - # - # - # - # -
# - # - # - # - # - # - # - # - #
# # - # - # - # - # - # - # - # -
# - # - # - # - # - # - # - # - #

As you can see, the automaton evolves into a complex and interesting pattern.

using System;
using System.Collections.Generic;

namespace prog
{
	class MainClass
	{	
		const int n_iter = 10;
		static int[] f = { 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 0 };
		
		public static void Main (string[] args)
		{
			for( int i=0; i<f.Length; i++ )
				Console.Write( f[i]==0 ? "-" : "#" );
			Console.WriteLine("");			
			
			int[] g = new int[f.Length];
			for( int n=n_iter; n!=0; n-- )
			{
				for( int i=1; i<f.Length-1; i++ )
				{
					if ( (f[i-1] ^ f[i+1]) == 1 ) g[i] = f[i];
					else if ( f[i] == 0 && (f[i-1] & f[i+1]) == 1 ) g[i] = 1;
					else g[i] = 0;
				}
				g[0] = ( (f[0] & f[1]) == 1 ) ? 1 : 0;
				g[g.Length-1] = ( (f[f.Length-1] & f[f.Length-2]) == 1 ) ? 1 : 0;
				
				int[] tmp = f;
				f = g;
				g = tmp;
				
				for( int i=0; i<f.Length; i++ )
					Console.Write( f[i]==0 ? "-" : "#" );
				Console.WriteLine("");
			}			
		}
	}
}