How to resolve the algorithm Palindrome detection step by step in the Julia programming language
How to resolve the algorithm Palindrome detection step by step in the Julia programming language
Table of Contents
Problem Statement
A palindrome is a phrase which reads the same backward and forward. Write a function or program that checks whether a given sequence of characters (or, if you prefer, bytes) is a palindrome. For extra credit:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Palindrome detection step by step in the Julia programming language
The provided Julia code defines three different functions named palindrome
to check if a given string s
is a palindrome. A palindrome is a string that reads the same forward and backward. Here's a detailed explanation of each function:
-
First Function:
palindrome(s) = s == reverse(s)
This function takes a string
s
as input and returns a boolean value indicating whethers
is a palindrome. It uses Julia's built-in==
operator to compare the original strings
with its reversed versionreverse(s)
. If the two strings are equal, it means the string is a palindrome and the function returnstrue
. Otherwise, it returnsfalse
. -
Second Function:
function palindrome(s) len = length(s) for i = 1:(len/2) if(s[len-i+1]!=s[i]) return false end end return true end
This function also takes a string
s
as input. It first calculates the length of the stringlen
using thelength
function. Then, it iterates through the first half of the string (up tolen/2
) using afor
loop. Inside the loop, it compares each character at positioni
with its corresponding character at positionlen-i+1
. If any pair of characters doesn't match, it means the string is not a palindrome, and the function returnsfalse
. If the loop completes without finding any mismatched characters, it means the string is a palindrome, and the function returnstrue
. -
Third Function:
function palindrome(s) len = length(s) if(len==0 || len==1) return true end if(s[1] == s[len]) return palindrome(SubString(s,2,len-1)) end return false end
This function uses a recursive approach to check if a string
s
is a palindrome. It first checks if the string is empty or has only one character, in which case it returnstrue
because empty strings and single-character strings are considered palindromes.If neither of those conditions is met, it compares the first and last characters of the string. If they match, the function recursively calls itself with a substring of
s
excluding the first and last characters (i.e.,SubString(s,2,len-1)
). This recursive process continues until the substring becomes empty or has only one character, at which point the function returnstrue
. If the first and last characters don't match, the function returnsfalse
.
Source code in the julia programming language
palindrome(s) = s == reverse(s)
function palindrome(s)
len = length(s)
for i = 1:(len/2)
if(s[len-i+1]!=s[i])
return false
end
end
return true
end
function palindrome(s)
len = length(s)
if(len==0 || len==1)
return true
end
if(s[1] == s[len])
return palindrome(SubString(s,2,len-1))
end
return false
end
You may also check:How to resolve the algorithm Object serialization step by step in the Common Lisp programming language
You may also check:How to resolve the algorithm Happy numbers step by step in the Python programming language
You may also check:How to resolve the algorithm Sexy primes step by step in the Lua programming language
You may also check:How to resolve the algorithm Catalan numbers/Pascal's triangle step by step in the Lua programming language
You may also check:How to resolve the algorithm Multiplication tables step by step in the Delphi programming language