How to resolve the algorithm Pentagram step by step in the REXX programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Pentagram step by step in the REXX programming language
Table of Contents
Problem Statement
A pentagram is a star polygon, consisting of a central pentagon of which each side forms the base of an isosceles triangle. The vertex of each triangle, a point of the star, is 36 degrees.
Draw (or print) a regular pentagram, in any orientation. Use a different color (or token) for stroke and fill, and background. For the fill it should be assumed that all points inside the triangles and the pentagon are inside the pentagram.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Pentagram step by step in the REXX programming language
Source code in the rexx programming language
/* REXX ***************************************************************
* Create a BMP file showing a pentagram
**********************************************************************/
Parse Version v
If pos('Regina',v)>0 Then
pentagram='pentagrama.bmp'
Else
pentagram='pentagramx.bmp'
'erase' pentagram
s='424d4600000000000000360000002800000038000000280000000100180000000000'X||,
'1000000000000000000000000000000000000000'x
Say 'sl='length(s)
z.0=0
white='ffffff'x
red ='00ff00'x
green='ff0000'x
blue ='0000ff'x
rd6=copies(rd,6)
m=133
m=80
n=80
hor=m*8 /* 56 */
ver=n*8 /* 40 */
Say 'hor='hor
Say 'ver='ver
Say 'sl='length(s)
s=overlay(lend(hor),s,19,4)
s=overlay(lend(ver),s,23,4)
Say 'sl='length(s)
z.=copies('ffffff'x,3192%3)
z.=copies('ffffff'x,8*m)
z.0=648
pi_5=2*3.14159/5
s72 =sin(pi_5 )
c72 =cos(pi_5 )
s144=sin(pi_5*2)
c144=cos(pi_5*2)
xm=300
ym=300
r=200
p.0x.1=xm
p.0y.1=ym+r
p.0x.2=format(xm+r*s72,3,0)
p.0y.2=format(ym+r*c72,3,0)
p.0x.3=format(xm+r*s144,3,0)
p.0y.3=format(ym+r*c144,3,0)
p.0x.4=format(xm-r*s144,3,0)
p.0y.4=p.0y.3
p.0x.5=format(xm-r*s72,3,0)
p.0y.5=p.0y.2
Do i=1 To 5
Say p.0x.i p.0y.i
End
Call line p.0x.1,p.0y.1,p.0x.3,p.0y.3
Call line p.0x.1,p.0y.1,p.0x.4,p.0y.4
Call line p.0x.2,p.0y.2,p.0x.4,p.0y.4
Call line p.0x.2,p.0y.2,p.0x.5,p.0y.5
Call line p.0x.3,p.0y.3,p.0x.5,p.0y.5
Do i=1 To z.0
s=s||z.i
End
Call lineout pentagram,s
Call lineout pentagram
Exit
lend:
Return reverse(d2c(arg(1),4))
line: Procedure Expose z. red green blue
Parse Arg x0, y0, x1, y1
Say 'line' x0 y0 x1 y1
dx = abs(x1-x0)
dy = abs(y1-y0)
if x0 < x1 then sx = 1
else sx = -1
if y0 < y1 then sy = 1
else sy = -1
err = dx-dy
Do Forever
xxx=x0*3+2
Do yy=y0-1 To y0+1
z.yy=overlay(copies(blue,5),z.yy,xxx)
End
if x0 = x1 & y0 = y1 Then Leave
e2 = 2*err
if e2 > -dy then do
err = err - dy
x0 = x0 + sx
end
if e2 < dx then do
err = err + dx
y0 = y0 + sy
end
end
Return
sin: Procedure
/* REXX ****************************************************************
* Return sin(x<,p>) -- with the specified precision
***********************************************************************/
Parse Arg x,prec
If prec='' Then prec=9
Numeric Digits (2*prec)
Numeric Fuzz 3
pi=3.14159
Do While x>pi
x=x-pi
End
Do While x<-pi
x=x+pi
End
o=x
u=1
r=x
Do i=3 By 2
ra=r
o=-o*x*x
u=u*i*(i-1)
r=r+(o/u)
If r=ra Then Leave
End
Numeric Digits prec
Return r+0
cos: Procedure
/* REXX ****************************************************************
* Return cos(x) -- with specified precision
***********************************************************************/
Parse Arg x,prec
If prec='' Then prec=9
Numeric Digits (2*prec)
Numeric Fuzz 3
o=1
u=1
r=1
Do i=1 By 2
ra=r
o=-o*x*x
u=u*i*(i+1)
r=r+(o/u)
If r=ra Then Leave
End
Numeric Digits prec
Return r+0
sqrt: Procedure
/* REXX ***************************************************************
* EXEC to calculate the square root of a = 2 with high precision
**********************************************************************/
Parse Arg x,prec
If prec<9 Then prec=9
prec1=2*prec
eps=10**(-prec1)
k = 1
Numeric Digits 3
r0= x
r = 1
Do i=1 By 1 Until r=r0 | (abs(r*r-x)
r0 = r
r = (r + x/r) / 2
k = min(prec1,2*k)
Numeric Digits (k + 5)
End
Numeric Digits prec
Return r+0
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