How to resolve the algorithm Perfect numbers step by step in the C# programming language
How to resolve the algorithm Perfect numbers step by step in the C# programming language
Table of Contents
Problem Statement
Write a function which says whether a number is perfect.
A perfect number is a positive integer that is the sum of its proper positive divisors excluding the number itself. Equivalently, a perfect number is a number that is half the sum of all of its positive divisors (including itself).
Note: The faster Lucas-Lehmer test is used to find primes of the form 2n-1, all known perfect numbers can be derived from these primes using the formula (2n - 1) × 2n - 1. It is not known if there are any odd perfect numbers (any that exist are larger than 102000). The number of known perfect numbers is 51 (as of December, 2018), and the largest known perfect number contains 49,724,095 decimal digits.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Perfect numbers step by step in the C# programming language
General Overview: This C# code identifies and prints perfect numbers within the range of 1 to 33,550,337. A perfect number is a positive integer whose sum of all its positive proper divisors (excluding itself) equals the number itself.
First Implementation: Main Method:
- The
Main
method prints a message indicating that it will find perfect numbers in the specified range. - It enters a loop to iterate through all numbers from 0 to 33,550,337.
IsPerfect Method:
- The
IsPerfect
method checks if a given number is perfect. - It initializes a variable
sum
to 0. - It iterates through all numbers from 1 to the number, excluding the number itself.
- For each number
i
, it checks ifnum
is divisible byi
(i.e.,num % i == 0
). If so, it addsi
tosum
. - Finally, it returns if
sum
is equal tonum
, indicating that the number is perfect.
Second Implementation: Main Method:
- Same as the first implementation.
IsPerfect Method:
- Uses LINQ to simplify the calculation of the sum of proper divisors.
- It uses the
Enumerable.Range
method to create a sequence of numbers from 1 tonum - 1
. - It applies the
Sum
method to the sequence, with a lambda expression that checks ifnum
is divisible by each numbern
and addsn
to the running sum if divisible. - If the resulting sum is equal to
num
, the method returnstrue
to indicate that the number is perfect.
Usage:
- Both implementations iterate through the entire range of numbers from 1 to 33,550,337.
- For each number, they calculate the sum of its proper divisors using the
IsPerfect
method. - If the sum is equal to the number, they print the number as a perfect number.
- The user can interact with the program by pressing any key after the program finishes executing to close the console window.
Source code in the csharp programming language
static void Main(string[] args)
{
Console.WriteLine("Perfect numbers from 1 to 33550337:");
for (int x = 0; x < 33550337; x++)
{
if (IsPerfect(x))
Console.WriteLine(x + " is perfect.");
}
Console.ReadLine();
}
static bool IsPerfect(int num)
{
int sum = 0;
for (int i = 1; i < num; i++)
{
if (num % i == 0)
sum += i;
}
return sum == num ;
}
static void Main(string[] args)
{
Console.WriteLine("Perfect numbers from 1 to 33550337:");
for (int x = 0; x < 33550337; x++)
{
if (IsPerfect(x))
Console.WriteLine(x + " is perfect.");
}
Console.ReadLine();
}
static bool IsPerfect(int num)
{
return Enumerable.Range(1, num - 1).Sum(n => num % n == 0 ? n : 0 ) == num;
}
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