How to resolve the algorithm Pernicious numbers step by step in the Quackery programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Pernicious numbers step by step in the Quackery programming language
Table of Contents
Problem Statement
A pernicious number is a positive integer whose population count is a prime. The population count is the number of ones in the binary representation of a non-negative integer.
22 (which is 10110 in binary) has a population count of 3, which is prime, and therefore
22 is a pernicious number.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Pernicious numbers step by step in the Quackery programming language
Source code in the quackery programming language
[ $ "rosetta/seive.qky" loadfile
$ "rosetta/popcount.qky" loadfile ] now!
( i.e. using the code at )
( http://rosettacode.org/wiki/Sieve_of_Eratosthenes and )
( http://rosettacode.org/wiki/Population_count )
29 eratosthenes ( Precompute as many primes as are required )
( for the task. 888,888,888 is a 30 bit )
( number less than (2^30)-1 so primes up to )
( 29 will suffice. )
[ 1+ over - times
[ dup i^ +
dup popcount
isprime iff
[ echo sp ]
else drop ]
drop ] is perniciousrange ( n n --> )
25 echopopwith isprime cr
888888877 888888888 perniciousrange cr
You may also check:How to resolve the algorithm Conditional structures step by step in the HicEst programming language
You may also check:How to resolve the algorithm Stack step by step in the AWK programming language
You may also check:How to resolve the algorithm Collections step by step in the PARI/GP programming language
You may also check:How to resolve the algorithm Number reversal game step by step in the Inform 7 programming language
You may also check:How to resolve the algorithm Loops/Infinite step by step in the Phixmonti programming language