How to resolve the algorithm Power set step by step in the J programming language

Published on 12 May 2024 09:40 PM
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How to resolve the algorithm Power set step by step in the J programming language

Table of Contents

Problem Statement

A   set   is a collection (container) of certain values, without any particular order, and no repeated values. It corresponds with a finite set in mathematics. A set can be implemented as an associative array (partial mapping) in which the value of each key-value pair is ignored. Given a set S, the power set (or powerset) of S, written P(S), or 2S, is the set of all subsets of S.

By using a library or built-in set type, or by defining a set type with necessary operations, write a function with a set S as input that yields the power set 2S of S.

For example, the power set of     {1,2,3,4}     is For a set which contains n elements, the corresponding power set has 2n elements, including the edge cases of empty set. The power set of the empty set is the set which contains itself (20 = 1): And the power set of the set which contains only the empty set, has two subsets, the empty set and the set which contains the empty set (21 = 2):

Extra credit: Demonstrate that your language supports these last two powersets.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Power set step by step in the J programming language

Source code in the j programming language

ps =: #~ 2 #:@i.@^ #


   ps 'ACE'
   
E  
C  
CE 
A  
AE 
AC 
ACE


   ~.1 2 3 2 1
1 2 3
   #ps 1 2 3 2 1
32
   #ps ~.1 2 3 2 1
8


  

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