How to resolve the algorithm Product of min and max prime factors step by step in the Cowgol programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Product of min and max prime factors step by step in the Cowgol programming language
Table of Contents
Problem Statement
Exactly as the task title implies.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Product of min and max prime factors step by step in the Cowgol programming language
Source code in the cowgol programming language
include "cowgol.coh";
const MAX := 100;
var prime: uint8[MAX+1];
typedef N is @indexof prime;
sub Sieve() is
prime[0] := 0;
prime[1] := 0;
MemSet(&prime[2], 1, @bytesof prime-2);
var p: N := 2;
while p*p <= MAX loop
var c: N := p*p;
while c <= MAX loop
prime[c] := 0;
c := c + p;
end loop;
p := p + 1;
end loop;
end sub;
sub LowFactor(n: N): (f: N) is
if n == 1 then f := 1; return; end if;
f := 2;
while f <= n loop
if prime[f] == 1 and n%f == 0 then return; end if;
f := f + 1;
end loop;
end sub;
sub HighFactor(n: N): (f: N) is
if n == 1 then f := 1; return; end if;
f := n;
while f >= 2 loop
if prime[f] == 1 and n%f == 0 then return; end if;
f := f - 1;
end loop;
end sub;
Sieve();
var i: N := 1;
while i <= MAX loop
print_i16(LowFactor(i) as uint16 * HighFactor(i) as uint16);
if i % 10 == 0
then print_nl();
else print_char('\t');
end if;
i := i + 1;
end loop;
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