How to resolve the algorithm Product of min and max prime factors step by step in the PL/M programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Product of min and max prime factors step by step in the PL/M programming language
Table of Contents
Problem Statement
Exactly as the task title implies.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Product of min and max prime factors step by step in the PL/M programming language
Source code in the pl/m programming language
100H: /* FIND THE PRODUCT OF THE MIN AND MAX PRIME FACTORS OF SOME NUMBERS */
DECLARE FALSE LITERALLY '0', TRUE LITERALLY '0FFH';
/* CP/M SYSTEM CALL AND I/O ROUTINES */
BDOS: PROCEDURE( FN, ARG ); DECLARE FN BYTE, ARG ADDRESS; GOTO 5; END;
PR$CHAR: PROCEDURE( C ); DECLARE C BYTE; CALL BDOS( 2, C ); END;
PR$STRING: PROCEDURE( S ); DECLARE S ADDRESS; CALL BDOS( 9, S ); END;
PR$NL: PROCEDURE; CALL PR$CHAR( 0DH ); CALL PR$CHAR( 0AH ); END;
PR$NUMBER: PROCEDURE( N ); /* PRINTS A NUMBER IN THE MINIMUN FIELD WIDTH */
DECLARE N ADDRESS;
DECLARE V ADDRESS, N$STR ( 6 )BYTE, W BYTE;
V = N;
W = LAST( N$STR );
N$STR( W ) = '$';
N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
DO WHILE( ( V := V / 10 ) > 0 );
N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
END;
CALL PR$STRING( .N$STR( W ) );
END PR$NUMBER;
/* END SYSTEM CALL AND I/O ROUTINES */
DECLARE MAX$N LITERALLY '100', /* MAXIMUM NUMBER TO CONSIDER */
MAX$N$PLUS$1 LITERALLY '101'; /* MAX$N + 1 FOR ARRAY BOUNDS */
/* SIEVE THE PRIMES TO MAX$N */
DECLARE PRIME ( MAX$N$PLUS$1 )BYTE;
DO;
DECLARE ( I, S ) ADDRESS;
PRIME( 0 ), PRIME( 1 ) = FALSE;
PRIME( 2 ) = TRUE;
DO I = 3 TO LAST( PRIME ) BY 2; PRIME( I ) = TRUE; END;
DO I = 4 TO LAST( PRIME ) BY 2; PRIME( I ) = FALSE; END;
DO I = 3 TO LAST( PRIME ) / 2 BY 2;
IF PRIME( I ) THEN DO;
DO S = I + I TO LAST( PRIME ) BY I; PRIME( S ) = FALSE; END;
END;
END;
END;
/* CONSTRUCT TABLES OF THE MINIMUM AND MAXIMUM PRIME FACTORS OF NUMBERS */
/* UP TO MAX$N */
DECLARE ( MIN$PF, MAX$PF ) ( MAX$N$PLUS$1 )ADDRESS;
DECLARE ( I, J ) BYTE;
DECLARE PRODUCT ADDRESS;
DO I = 1 TO LAST( MIN$PF );
MIN$PF( I ), MAX$PF( I ) = 0;
END;
MIN$PF( 1 ) = 1;
MAX$PF( 1 ) = 1;
DO I = 1 TO MAX$N;
IF PRIME( I ) THEN DO;
DO J = I TO MAX$N BY I;
IF MIN$PF( J ) = 0 THEN MIN$PF( J ) = I;
MAX$PF( J ) = I;
END;
END;
END;
/* PRINT THE PRODUCTS OF THE MIN AND MAX PRIME FACTORS */
DO I = 1 TO MAX$N;
PRODUCT = MIN$PF( I ) * MAX$PF( I );
IF PRODUCT < 10 THEN CALL PR$CHAR( ' ' );
IF PRODUCT < 100 THEN CALL PR$CHAR( ' ' );
IF PRODUCT < 1000 THEN CALL PR$CHAR( ' ' );
CALL PR$CHAR( ' ' );
CALL PR$NUMBER( PRODUCT );
IF I MOD 10 = 0 THEN CALL PR$NL;
END;
EOF
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