How to resolve the algorithm Product of min and max prime factors step by step in the C++ programming language
Published on 7 June 2024 03:52 AM
How to resolve the algorithm Product of min and max prime factors step by step in the C++ programming language
Table of Contents
Problem Statement
Exactly as the task title implies.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Product of min and max prime factors step by step in the C++ programming language
The C++ program determines the prime factorization of numbers from 1 to 100 and calculates the product of the smallest and largest prime factors for each number. Here's a detailed explanation of the code:
-
Header Inclusions:
- The program includes the necessary headers:
<iomanip>
: Used for manipulating input and output.<iostream>
: For input/output operations.<utility>
: For using thestd::pair
data structure.
- The program includes the necessary headers:
-
Function
min_max_prime_factors
:- This function takes an unsigned integer
n
as input and returns a pair of unsigned integers containing the minimum and maximum prime factors ofn
. - It initializes
min_factor
andmax_factor
to 1. - It checks if
n
is even (divisible by 2) using(n & 1) == 0
. If so, it repeatedly dividesn
by 2 while it's even, and updatesmin_factor
andmax_factor
to 2. - It then iterates through prime numbers starting from 3, incrementing by 2 in each iteration (
p += 2
). - For each prime number
p
, it checks ifn
is divisible byp
. If so, it repeatedly dividesn
byp
while it's divisible byp
, updatingmin_factor
top
if it's the first prime factor found, and updatingmax_factor
top
. - If
n
is still greater than 1 after the loop, it means thatn
itself is a prime factor. In this case, it updatesmin_factor
andmax_factor
ton
if they're still 1. - Finally, the function returns a
std::pair
containingmin_factor
andmax_factor
.
- This function takes an unsigned integer
-
Main Function:
-
The
main
function calculates the product of the smallest and greatest prime factors for numbers from 1 to 100. -
It uses a
for
loop to iterate through numbers from 1 to 100. -
For each number
n
, it callsmin_max_prime_factors(n)
to get the pair of prime factors. -
It then calculates the product of the prime factors and prints it, formatted with a width of 4.
-
It prints a newline every 10 numbers to improve readability.
-
-
Output:
- The program prints the product of the smallest and greatest prime factors of numbers from 1 to 100, each on a separate line. For example, for
n=6
, the smallest prime factor is 2 and the greatest prime factor is 3, so the product is 2 * 3 = 6. Forn=12
, the smallest prime factor is 2 and the greatest is 3, so the product is 2 * 3 = 6, and so on.
- The program prints the product of the smallest and greatest prime factors of numbers from 1 to 100, each on a separate line. For example, for
Source code in the cpp programming language
#include <iomanip>
#include <iostream>
#include <utility>
auto min_max_prime_factors(unsigned int n) {
unsigned int min_factor = 1;
unsigned int max_factor = 1;
if ((n & 1) == 0) {
while ((n & 1) == 0)
n >>= 1;
min_factor = 2;
max_factor = 2;
}
for (unsigned int p = 3; p * p <= n; p += 2) {
if (n % p == 0) {
while (n % p == 0)
n /= p;
if (min_factor == 1)
min_factor = p;
max_factor = p;
}
}
if (n > 1) {
if (min_factor == 1)
min_factor = n;
max_factor = n;
}
return std::make_pair(min_factor, max_factor);
}
int main() {
std::cout << "Product of smallest and greatest prime factors of n for 1 to "
"100:\n";
for (unsigned int n = 1; n <= 100; ++n) {
auto p = min_max_prime_factors(n);
std::cout << std::setw(4) << p.first * p.second
<< (n % 10 == 0 ? '\n' : ' ');
}
}
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