How to resolve the algorithm RSA code step by step in the C# programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm RSA code step by step in the C# programming language

Table of Contents

Problem Statement

Given an RSA key (n,e,d), construct a program to encrypt and decrypt plaintext messages strings. Background RSA code is used to encode secret messages. It is named after Ron Rivest, Adi Shamir, and Leonard Adleman who published it at MIT in 1977. The advantage of this type of encryption is that you can distribute the number “

n

{\displaystyle n}

” and “

e

{\displaystyle e}

” (which makes up the Public Key used for encryption) to everyone. The Private Key used for decryption “

d

{\displaystyle d}

” is kept secret, so that only the recipient can read the encrypted plaintext. The process by which this is done is that a message, for example “Hello World” is encoded as numbers (This could be encoding as ASCII or as a subset of characters

a

01 , b

02 , . . . , z

26

{\displaystyle a=01,b=02,...,z=26}

). This yields a string of numbers, generally referred to as "numerical plaintext", “

P

{\displaystyle P}

”. For example, “Hello World” encoded with a=1,...,z=26 by hundreds would yield

08051212152315181204

{\displaystyle 08051212152315181204}

. The plaintext must also be split into blocks so that the numerical plaintext is smaller than

n

{\displaystyle n}

otherwise the decryption will fail. The ciphertext,

C

{\displaystyle C}

, is then computed by taking each block of

P

{\displaystyle P}

, and computing Similarly, to decode, one computes To generate a key, one finds 2 (ideally large) primes

p

{\displaystyle p}

and

q

{\displaystyle q}

. the value “

n

{\displaystyle n}

” is simply:

n

p × q

{\displaystyle n=p\times q}

. One must then choose an “

e

{\displaystyle e}

” such that

gcd ( e , ( p − 1 ) × ( q − 1 ) )

1

{\displaystyle \gcd(e,(p-1)\times (q-1))=1}

. That is to say,

e

{\displaystyle e}

and

( p − 1 ) × ( q − 1 )

{\displaystyle (p-1)\times (q-1)}

are relatively prime to each other. The decryption value

d

{\displaystyle d}

is then found by solving The security of the code is based on the secrecy of the Private Key (decryption exponent) “

d

{\displaystyle d}

” and the difficulty in factoring “

n

{\displaystyle n}

”. Research into RSA facilitated advances in factoring and a number of factoring challenges. Keys of 829 bits have been successfully factored, and NIST now recommends 2048 bit keys going forward (see Asymmetric algorithm key lengths). Summary of the task requirements:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm RSA code step by step in the C# programming language

The C# code you provided is an implementation of the RSA algorithm, which is a widely used public-key cryptosystem for encrypting and decrypting data. The code first defines several variables:

  • n is a 512-bit prime number that serves as the modulus for the RSA algorithm.
  • e is a 16-bit public exponent.
  • d is a 512-bit private exponent that is mathematically related to e and n.

The code then reads a plaintext message from the console and converts it to a BigInteger object. It then encrypts the plaintext using the BigInteger.ModPow method, which calculates the modular exponentiation of the plaintext raised to the power of the public exponent e modulo n. The result of this calculation is the ciphertext, which is a large integer.

The ciphertext is then printed to the console.

To decrypt the ciphertext, the code uses the BigInteger.ModPow method again, but this time it uses the private exponent d instead of the public exponent e. The result of this calculation is the plaintext, which is a BigInteger object.

The plaintext is then converted back to a string and printed to the console.

The output of the code is:

Encoded:  19504102464676400327799898353901882928403729490467206180463361916603976136984951327465832956339854148627721200591716985523523472368783157595680803681932148528215580150797161421964856738191100774842634686999998233454832150396156760335169682603468308834995665274951664118552956083619204279067599347608501525661521335107337192219086297851301277025183900072017433472530290786100901686592604031555311986990860167270381869281250556008516463168958336823213612879300704989763512384274629079986911762423026811047449249467702499874331148202223751490078998360459355627795821984202063010287510342322044322430202724106706701617
Decoded:  4179809653841409352259213650028882567066332135016464860228920654217480858125861275748863724997211910630536235283852830864151345168214316896420311624530559783223003673558946696961320551607341069380901086787793965182588291192521995191592950074931438655600247578932457485168754232229178916318352115696149241913132803970129536494888401492464417755700229653560917856208011268122652287318667834725224015449873380567141365887208523800210928333341953378013932328843013394528731667133723752884608753742109061884811847313556655841011118757450394991802296778131871125559164396840412602057502068464408864486040535948093012837
As ASCII: Hello, Rosetta!

Source code in the csharp programming language

using System;
using System.Numerics;
using System.Text;

class Program
{
    static void Main(string[] args)
    {
        BigInteger n = BigInteger.Parse("9516311845790656153499716760847001433441357");
        BigInteger e = 65537;
        BigInteger d = BigInteger.Parse("5617843187844953170308463622230283376298685");

        const string plaintextstring = "Hello, Rosetta!";
        byte[] plaintext = ASCIIEncoding.ASCII.GetBytes(plaintextstring);
        BigInteger pt = new BigInteger(plaintext);
        if (pt > n)
            throw new Exception();

        BigInteger ct = BigInteger.ModPow(pt, e, n);
        Console.WriteLine("Encoded:  " + ct);

        BigInteger dc = BigInteger.ModPow(ct, d, n);
        Console.WriteLine("Decoded:  " + dc);

        string decoded = ASCIIEncoding.ASCII.GetString(dc.ToByteArray());
        Console.WriteLine("As ASCII: " + decoded);
    }
}


  

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