How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the C programming language
How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the C programming language
Table of Contents
Problem Statement
The Ramer–Douglas–Peucker algorithm is a line simplification algorithm for reducing the number of points used to define its shape.
Using the Ramer–Douglas–Peucker algorithm, simplify the 2D line defined by the points: The error threshold to be used is: 1.0. Display the remaining points here.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the C programming language
This C code implements the Douglas-Peucker (DP) algorithm to simplify a given array of points, reducing the number of points while preserving the overall shape of the original curve. Below is a breakdown of the code:
-
Data Structures:
point_t
: A C struct representing a point withx
andy
coordinates.
-
Functions:
perpendicular_distance
: Calculates the perpendicular distance from a pointp
to a line segment defined by pointsp1
andp2
.douglas_peucker
: Implements the Douglas-Peucker algorithm, taking an array of points, the number of points, a distance toleranceepsilon
, and destination bufferdest
to store the simplified points.
-
Algorithm Description:
- Main Loop:
- The algorithm iterates over all points between
points[1]
andpoints[n-1]
, except the endpoints. - For each point, it calculates the perpendicular distance to the line segment connecting
points[0]
andpoints[n-1]
. - It tracks the point with the maximum distance from this line segment and stores its index in
index
.
- The algorithm iterates over all points between
- Recursive Calls:
- If the maximum distance exceeds the tolerance
epsilon
, the algorithm recursively calls itself on two subsets of points:points[0]
topoints[index+1]
points[index]
topoints[n-1]
- The number of output points in each recursive call is returned and accumulated in the total count.
- If the maximum distance exceeds the tolerance
- Base Case:
- If the maximum distance is less than or equal to
epsilon
, the algorithm returns the two endpoints as the simplified curve.
- If the maximum distance is less than or equal to
- Main Loop:
-
print_points
: A utility function to print the points in an array. -
main
Function:- Defines an array of sample points (
points
) and its length (len
). - Invokes
douglas_peucker
to simplify the points with a tolerance of1.0
and stores the result inout
. - Prints the simplified points using
print_points
.
- Defines an array of sample points (
In summary, this code reduces the number of points in an input array while maintaining the original curve's essential shape. This technique is useful in various applications, such as data simplification, image compression, and computer graphics.
Source code in the c programming language
#include <assert.h>
#include <math.h>
#include <stdio.h>
typedef struct point_tag {
double x;
double y;
} point_t;
// Returns the distance from point p to the line between p1 and p2
double perpendicular_distance(point_t p, point_t p1, point_t p2) {
double dx = p2.x - p1.x;
double dy = p2.y - p1.y;
double d = sqrt(dx * dx + dy * dy);
return fabs(p.x * dy - p.y * dx + p2.x * p1.y - p2.y * p1.x)/d;
}
// Simplify an array of points using the Ramer–Douglas–Peucker algorithm.
// Returns the number of output points.
size_t douglas_peucker(const point_t* points, size_t n, double epsilon,
point_t* dest, size_t destlen) {
assert(n >= 2);
assert(epsilon >= 0);
double max_dist = 0;
size_t index = 0;
for (size_t i = 1; i + 1 < n; ++i) {
double dist = perpendicular_distance(points[i], points[0], points[n - 1]);
if (dist > max_dist) {
max_dist = dist;
index = i;
}
}
if (max_dist > epsilon) {
size_t n1 = douglas_peucker(points, index + 1, epsilon, dest, destlen);
if (destlen >= n1 - 1) {
destlen -= n1 - 1;
dest += n1 - 1;
} else {
destlen = 0;
}
size_t n2 = douglas_peucker(points + index, n - index, epsilon, dest, destlen);
return n1 + n2 - 1;
}
if (destlen >= 2) {
dest[0] = points[0];
dest[1] = points[n - 1];
}
return 2;
}
void print_points(const point_t* points, size_t n) {
for (size_t i = 0; i < n; ++i) {
if (i > 0)
printf(" ");
printf("(%g, %g)", points[i].x, points[i].y);
}
printf("\n");
}
int main() {
point_t points[] = {
{0,0}, {1,0.1}, {2,-0.1}, {3,5}, {4,6},
{5,7}, {6,8.1}, {7,9}, {8,9}, {9,9}
};
const size_t len = sizeof(points)/sizeof(points[0]);
point_t out[len];
size_t n = douglas_peucker(points, len, 1.0, out, len);
print_points(out, n);
return 0;
}
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