How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Java programming language
How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Java programming language
Table of Contents
Problem Statement
The Ramer–Douglas–Peucker algorithm is a line simplification algorithm for reducing the number of points used to define its shape.
Using the Ramer–Douglas–Peucker algorithm, simplify the 2D line defined by the points: The error threshold to be used is: 1.0. Display the remaining points here.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Java programming language
The provided Java code demonstrates the Ramer-Douglas-Peucker (RDP) algorithm for simplifying a polyline by reducing the number of points while preserving its overall shape. The algorithm works as follows:
-
Point Class: It defines a
Point
class that extendsPair<Double, Double>
to represent points in two-dimensional space. -
Perpendicular Distance: The
perpendicularDistance
method calculates the perpendicular distance between a point and a line segment defined by two other points. -
Ramer-Douglas-Peucker Simplification: The
ramerDouglasPeucker
method recursively simplifies a list of points by finding the point with the maximum perpendicular distance from the line segment connecting the start and end points. If this distance exceeds a specifiedepsilon
, the line is further divided, and the algorithm is applied recursively to each segment. -
Main Function: The
main
function creates a sample list of points and calls theramerDouglasPeucker
method to simplify it with anepsilon
of 1.0. The simplified list is then printed to the console.
Here's a detailed explanation of each part of the code:
-
Point Class: The
Point
class is a simple extension ofPair<Double, Double>
that represents a point in two-dimensional space. It overrides thetoString
method to provide a convenient representation of the point as a string, e.g.,"(0.0, 0.0)"
. -
Perpendicular Distance: The
perpendicularDistance
method calculates the perpendicular distance between a pointpt
and a line segment defined by two other points,lineStart
andlineEnd
. It uses vector math to find the projection ofpt
onto the normalized direction vector of the line segment and then calculates the distance between the projected point andpt
. -
Ramer-Douglas-Peucker Simplification: The
ramerDouglasPeucker
method implements the RDP algorithm for simplifying polylines. It takes a list of points,pointList
, anepsilon
tolerance for the maximum perpendicular distance, and an output list,out
. It follows these steps:-
If the number of points in
pointList
is less than 2, it raises anIllegalArgumentException
because there are not enough points to simplify. -
It iterates through the points in
pointList
, excluding the first and last points, and calculates the perpendicular distance of each point from the line segment connecting the first and last points. The point with the maximum distance is stored inindex
with its distance indmax
. -
If
dmax
is greater thanepsilon
, indicating that the line is not sufficiently straight, it splitspointList
into two segments:firstLine
from the first to theindex
point andlastLine
from theindex
point to the last. It then recursively callsramerDouglasPeucker
on each segment, storing the results inrecResults1
andrecResults2
, respectively. -
It assembles the simplified result by combining the simplified first and last lines, removing the duplicate point at
index
. If the resulting output has less than two points, it throws aRuntimeException
. -
If
dmax
is less than or equal toepsilon
, it means the line segment is sufficiently straight, and it simply adds the first and last points to the output.
-
-
Main Function: The
main
function creates a sample list of pointspointList
and calls theramerDouglasPeucker
method to simplify it with anepsilon
of 1.0. The simplified list is stored inpointListOut
and printed to the console.
By running the program, you can see the original list of points and the simplified version that preserves the overall shape while reducing the number of points.
Source code in the java programming language
import javafx.util.Pair;
import java.util.ArrayList;
import java.util.List;
public class LineSimplification {
private static class Point extends Pair<Double, Double> {
Point(Double key, Double value) {
super(key, value);
}
@Override
public String toString() {
return String.format("(%f, %f)", getKey(), getValue());
}
}
private static double perpendicularDistance(Point pt, Point lineStart, Point lineEnd) {
double dx = lineEnd.getKey() - lineStart.getKey();
double dy = lineEnd.getValue() - lineStart.getValue();
// Normalize
double mag = Math.hypot(dx, dy);
if (mag > 0.0) {
dx /= mag;
dy /= mag;
}
double pvx = pt.getKey() - lineStart.getKey();
double pvy = pt.getValue() - lineStart.getValue();
// Get dot product (project pv onto normalized direction)
double pvdot = dx * pvx + dy * pvy;
// Scale line direction vector and subtract it from pv
double ax = pvx - pvdot * dx;
double ay = pvy - pvdot * dy;
return Math.hypot(ax, ay);
}
private static void ramerDouglasPeucker(List<Point> pointList, double epsilon, List<Point> out) {
if (pointList.size() < 2) throw new IllegalArgumentException("Not enough points to simplify");
// Find the point with the maximum distance from line between the start and end
double dmax = 0.0;
int index = 0;
int end = pointList.size() - 1;
for (int i = 1; i < end; ++i) {
double d = perpendicularDistance(pointList.get(i), pointList.get(0), pointList.get(end));
if (d > dmax) {
index = i;
dmax = d;
}
}
// If max distance is greater than epsilon, recursively simplify
if (dmax > epsilon) {
List<Point> recResults1 = new ArrayList<>();
List<Point> recResults2 = new ArrayList<>();
List<Point> firstLine = pointList.subList(0, index + 1);
List<Point> lastLine = pointList.subList(index, pointList.size());
ramerDouglasPeucker(firstLine, epsilon, recResults1);
ramerDouglasPeucker(lastLine, epsilon, recResults2);
// build the result list
out.addAll(recResults1.subList(0, recResults1.size() - 1));
out.addAll(recResults2);
if (out.size() < 2) throw new RuntimeException("Problem assembling output");
} else {
// Just return start and end points
out.clear();
out.add(pointList.get(0));
out.add(pointList.get(pointList.size() - 1));
}
}
public static void main(String[] args) {
List<Point> pointList = List.of(
new Point(0.0, 0.0),
new Point(1.0, 0.1),
new Point(2.0, -0.1),
new Point(3.0, 5.0),
new Point(4.0, 6.0),
new Point(5.0, 7.0),
new Point(6.0, 8.1),
new Point(7.0, 9.0),
new Point(8.0, 9.0),
new Point(9.0, 9.0)
);
List<Point> pointListOut = new ArrayList<>();
ramerDouglasPeucker(pointList, 1.0, pointListOut);
System.out.println("Points remaining after simplification:");
pointListOut.forEach(System.out::println);
}
}
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