How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Perl programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Perl programming language
Table of Contents
Problem Statement
The Ramer–Douglas–Peucker algorithm is a line simplification algorithm for reducing the number of points used to define its shape.
Using the Ramer–Douglas–Peucker algorithm, simplify the 2D line defined by the points: The error threshold to be used is: 1.0. Display the remaining points here.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Perl programming language
Source code in the perl programming language
use strict;
use warnings;
use feature 'say';
use List::MoreUtils qw(firstidx minmax);
my $epsilon = 1;
sub norm {
my(@list) = @_;
my $sum;
$sum += $_**2 for @list;
sqrt($sum)
}
sub perpendicular_distance {
our(@start,@end,@point);
local(*start,*end,*point) = (shift, shift, shift);
return 0 if $start[0]==$point[0] && $start[1]==$point[1]
or $end[0]==$point[0] && $end[1]==$point[1];
my ( $dx, $dy) = ( $end[0]-$start[0], $end[1]-$start[1]);
my ($dpx, $dpy) = ($point[0]-$start[0],$point[1]-$start[1]);
my $t = norm($dx, $dy);
$dx /= $t;
$dy /= $t;
norm($dpx - $dx*($dx*$dpx + $dy*$dpy), $dpy - $dy*($dx*$dpx + $dy*$dpy));
}
sub Ramer_Douglas_Peucker {
my(@points) = @_;
return @points if @points == 2;
my @d;
push @d, perpendicular_distance(@points[0, -1, $_]) for 0..@points-1;
my(undef,$dmax) = minmax @d;
my $index = firstidx { $_ == $dmax } @d;
if ($dmax > $epsilon) {
my @lo = Ramer_Douglas_Peucker( @points[0..$index]);
my @hi = Ramer_Douglas_Peucker( @points[$index..$#points]);
return @lo[0..@lo-2], @hi;
}
@points[0, -1];
}
say '(' . join(' ', @$_) . ') '
for Ramer_Douglas_Peucker( [0,0],[1,0.1],[2,-0.1],[3,5],[4,6],[5,7],[6,8.1],[7,9],[8,9],[9,9] )
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