How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Yabasic programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Yabasic programming language
Table of Contents
Problem Statement
The Ramer–Douglas–Peucker algorithm is a line simplification algorithm for reducing the number of points used to define its shape.
Using the Ramer–Douglas–Peucker algorithm, simplify the 2D line defined by the points: The error threshold to be used is: 1.0. Display the remaining points here.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Ramer-Douglas-Peucker line simplification step by step in the Yabasic programming language
Source code in the yabasic programming language
sub perpendicularDistance(tabla(), i, ini, fin)
local dx, cy, mag, pvx, pvy, pvdot, dsx, dsy, ax, ay
dx = tabla(fin, 1) - tabla(ini, 1)
dy = tabla(fin, 2) - tabla(ini, 2)
//Normalise
mag = (dx^2 + dy^2)^0.5
if mag > 0 dx = dx / mag : dy = dy / mag
pvx = tabla(i, 1) - tabla(ini, 1)
pvy = tabla(i, 2) - tabla(ini, 2)
//Get dot product (project pv onto normalized direction)
pvdot = dx * pvx + dy * pvy
//Scale line direction vector
dsx = pvdot * dx
dsy = pvdot * dy
//Subtract this from pv
ax = pvx - dsx
ay = pvy - dsy
return (ax^2 + ay^2)^0.5
end sub
sub DouglasPeucker(PointList(), ini, fin, epsilon)
local dmax, index, i, d
// Find the point with the maximum distance
for i = ini + 1 to fin
d = perpendicularDistance(PointList(), i, ini, fin)
if d > dmax index = i : dmax = d
next
// If max distance is greater than epsilon, recursively simplify
if dmax > epsilon then
PointList(index, 3) = true
// Recursive call
DouglasPeucker(PointList(), ini, index, epsilon)
DouglasPeucker(PointList(), index, fin, epsilon)
end if
end sub
data 0,0, 1,0.1, 2,-0.1, 3,5, 4,6, 5,7, 6,8.1, 7,9, 8,9, 9,9
dim matriz(10, 3)
for i = 1 to 10
read matriz(i, 1), matriz(i, 2)
next
DouglasPeucker(matriz(), 1, 10, 1)
matriz(1, 3) = true : matriz(10, 3) = true
for i = 1 to 10
if matriz(i, 3) print matriz(i, 1), matriz(i, 2)
next
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